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check if concatinated string obtained after reversing s1 and s2 both i...
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declare str1 varchar2(100) := 'abca'; str2 varchar2(100) := 'cba'; str varchar2(100); i int; j int; cnt int:=0; BEGIN --str:=str1||str2; for i in reverse 1.. length(str1) loop str:=str|| substr(str1,i,1); end loop; str1:=str; str:=''; for i in reverse 1.. length(str2) loop str:=str|| substr(str2,i,1); end loop; str2:=str; str:=str1||str2; --dbms_output.put_line(str1||' '|| str2||' '||str); i:=1; j:=length(str); while i<j loop if substr(str,i,1) != substr(str,j,1) then cnt:=cnt+1; end if; i:=i+1; j:=j-1; end loop; if cnt = 0 then dbms_output.put_line('A palindrome'); else dbms_output.put_line('minimum number of character replacements required is '|| cnt); end if; END;
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minimum number of character replacements required is 3