light blue zoda, C (gcc)

Language: Layout:

//gcc 5.4.0

#include  <stdio.h>

int main(void)
{
    printf("Hello, world!\n");
    return 0;
}https://play.google.com/store/apps/details?id=vrpatel0018.cprograms

//Prim's Algorithm

#include<stdio.h>
#include<stdlib.h>

#define infinity 9999
#define MAX 20
 
int G[MAX][MAX],spanning[MAX][MAX],n;
 
int prims();
 
int main()
{
    int i,j,total_cost;
    printf("Enter no. of vertices:");
    scanf("%d",&n);
    
    printf("\nEnter the adjacency matrix:\n");
    
    for(i=0;i<n;i++)
        for(j=0;j<n;j++)
            scanf("%d",&G[i][j]);
    
    total_cost=prims();
    printf("\nspanning tree matrix:\n");
    
    for(i=0;i<n;i++)
    {
        printf("\n");
        for(j=0;j<n;j++)
            printf("%d\t",spanning[i][j]);
    }
    
    printf("\n\nTotal cost of spanning tree=%d",total_cost);
    return 0;
}
 
int prims()
{
    int cost[MAX][MAX];
    int u,v,min_distance,distance[MAX],from[MAX];
    int visited[MAX],no_of_edges,i,min_cost,j;
    
    //create cost[][] matrix,spanning[][]
    for(i=0;i<n;i++)
        for(j=0;j<n;j++)
        {
            if(G[i][j]==0)
                cost[i][j]=infinity;
            else
                cost[i][j]=G[i][j];
                spanning[i][j]=0;
        }
        
    //initialise visited[],distance[] and from[]
    distance[0]=0;
    visited[0]=1;
    
    for(i=1;i<n;i++)
    {
        distance[i]=cost[0][i];
        from[i]=0;
        visited[i]=0;
    }
    
    min_cost=0;        //cost of spanning tree
    no_of_edges=n-1;        //no. of edges to be added
    
    while(no_of_edges>0)
    {
        //find the vertex at minimum distance from the tree
        min_distance=infinity;
        for(i=1;i<n;i++)
            if(visited[i]==0&&distance[i]<min_distance)
            {
                v=i;
                min_distance=distance[i];
            }
            
        u=from[v];
        
        //insert the edge in spanning tree
        spanning[u][v]=distance[v];
        spanning[v][u]=distance[v];
        no_of_edges--;
        visited[v]=1;
        
        //updated the distance[] array
        for(i=1;i<n;i++)
            if(visited[i]==0&&cost[i][v]<distance[i])
            {
                distance[i]=cost[i][v];
                from[i]=v;
            }
        
        min_cost=min_cost+cost[u][v];
    }
    
    return(min_cost);
}

Show compiler warnings [ + ] Compiler args [ + ] Show input