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map lambda list
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#python 3.5.2 def square(a): return a*a list1=[square] for i in range(5): val=list (map(lambda x:x(i),list1)) print(val) def fourista(a): return a*a*a*a list2=[fourista] for i in range(5): val2=list (map(lambda x:x(i),list2)) print(val2) print("new") def sq(a): return a*a num=[2,3,4,5,6,7,8] square=(list(map(sq,num))) print(square)
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Absolute running time: 0.15 sec, cpu time: 0.13 sec, memory peak: 6 Mb, absolute service time: 0,15 sec
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[0] [1] [4] [9] [16] [0] [1] [16] [81] [256] new [4, 9, 16, 25, 36, 49, 64]