Examen pregunta 1 - Angeles Gutiérrez José Luis, Prolog

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objeto:- write('{ '), read(X), a1(X), write('}').     
a1(X):- (X = 'atributo' -> atributo, write('')); write('').                                   
atributo:- read(X), write('"'), write(X), write('":'), tipoatributo(X), otro.                                                                                 
otro:- read(X), X = 'atributo' -> write(', '), atributo; write(' ').             
tipoatributo(M):- read(X), (X = 'metodo' -> metodo(M); (X = 'numero' -> numero; (X = 'cadena' -> cadena; (X = 'objeto' -> objeto; ( X = 'arreglo' -> arreglo, write(']')))))).
cadena:- read(X), write('"'), write(X), write('"'). 
numero:- read(X), write(X).
arreglo:- write('['), read(X), a0(X).
a0(X):- (X = 'numero' -> numero; 
         X = 'cadena' -> cadena; 
         X = 'objeto' -> objeto ;
         X = 'arreglo' -> arreglo, write(']')), otro1.
otro1:- read(X), (X = 'numero' -> write(', '), numero, otro1; 
                  X = 'cadena' -> write(', ') , cadena, otro1; 
                  X= 'objeto' -> write(', '), objeto, otro1;
                  X = 'arreglo' -> write('], '), arreglo; a1(X)).
metodo(M):- write('"function() {'),a2,write(' return '), write(M), write(';}"').
a2:- read(X), (X='decision'->decision;a3(X)).
a3(X):- X='asignacion' -> asignacion;(a4(X)).
a4(X):- X='fin' -> write('');(write('ERROR: '),write(X)).
asignacion:- read(X), write(X), write('='), read(Y), write(Y), write(';'),a2.
decision:- write('if('),condicion,write(')'), verdadero,falso.
condicion:-read(X), write(X).
verdadero:- write('{'),a2,write('}').
falso:- write('else {'),a2,write('}').
:- objeto.

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