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Math 9.64 (Edited makeMixedNum)

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\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 1. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(5\dfrac{7}{13}\times1\dfrac{15}{24}=\underline{\hspace{3cm}}\)\dfrac{9}{1}\)
        \item \(1\dfrac{8}{9}\times1\dfrac{13}{17}=\underline{\hspace{3cm}}\)\dfrac{10}{3}\)
        \item \(1\dfrac{6}{54}\times\dfrac{9}{85}=\underline{\hspace{3cm}}\)\dfrac{2}{17}\)
        \item \(\dfrac{36}{81}\div\dfrac{7}{84}=\underline{\hspace{3cm}}\)\dfrac{16}{3}\)
        \item \(6\dfrac{9}{12}+3\dfrac{1}{3}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(5\dfrac{2}{11}\times\dfrac{9}{27}=\underline{\hspace{3cm}}\)\dfrac{19}{11}\)
        \item \(\dfrac{21}{45}\div\dfrac{56}{72}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(1\dfrac{1}{15}\times7\dfrac{4}{8}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(\dfrac{10}{52}\times3\dfrac{2}{8}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(8\dfrac{2}{8}-9\dfrac{8}{12}=\underline{\hspace{3cm}}\)17\dfrac{11}{12}\)
        \item \(7\dfrac{9}{10}+9\dfrac{2}{8}=\underline{\hspace{3cm}}\)17\dfrac{3}{20}\)
        \item \(3\dfrac{4}{6}-9\dfrac{5}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{12}\)
        \item \(\dfrac{28}{90}\times\dfrac{21}{14}=\underline{\hspace{3cm}}\)\dfrac{7}{15}\)
        \item \(2\dfrac{18}{19}\times2\dfrac{25}{35}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(8\dfrac{7}{8}-5\dfrac{3}{12}=\underline{\hspace{3cm}}\)14\dfrac{1}{8}\)
        \item \(1\dfrac{2}{6}\times2\dfrac{2}{20}=\underline{\hspace{3cm}}\)\dfrac{14}{5}\)
        \item \(\dfrac{10}{72}\times2\dfrac{24}{30}=\underline{\hspace{3cm}}\)\dfrac{7}{18}\)
        \item \(\dfrac{23}{34}\times1\dfrac{3}{69}=\underline{\hspace{3cm}}\)\dfrac{12}{17}\)
        \item \(\dfrac{45}{36}\div\dfrac{18}{8}=\underline{\hspace{3cm}}\)\dfrac{5}{9}\)
        \item \(4\dfrac{6}{9}-7\dfrac{1}{4}=\underline{\hspace{3cm}}\)11\dfrac{11}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 2. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(6\dfrac{3}{4}-8\dfrac{1}{10}=\underline{\hspace{3cm}}\)14\dfrac{17}{20}\)
        \item \(2\dfrac{4}{8}-8\dfrac{4}{9}=\underline{\hspace{3cm}}\)10\dfrac{17}{18}\)
        \item \(\dfrac{45}{20}\div\dfrac{66}{16}=\underline{\hspace{3cm}}\)\dfrac{6}{11}\)
        \item \(3\dfrac{8}{10}-2\dfrac{4}{6}=\underline{\hspace{3cm}}\)6\dfrac{7}{15}\)
        \item \(9\dfrac{1}{6}-5\dfrac{1}{12}=\underline{\hspace{3cm}}\)14\dfrac{1}{4}\)
        \item \(\dfrac{26}{32}\div\dfrac{26}{16}=\underline{\hspace{3cm}}\)\dfrac{1}{2}\)
        \item \(5\dfrac{4}{6}+7\dfrac{2}{9}=\underline{\hspace{3cm}}\)12\dfrac{8}{9}\)
        \item \(6\dfrac{1}{2}-2\dfrac{3}{5}=\underline{\hspace{3cm}}\)9\dfrac{1}{10}\)
        \item \(\dfrac{24}{72}\times\dfrac{40}{30}=\underline{\hspace{3cm}}\)\dfrac{4}{9}\)
        \item \(9\dfrac{1}{2}-7\dfrac{1}{7}=\underline{\hspace{3cm}}\)16\dfrac{9}{14}\)
        \item \(\dfrac{48}{66}\div\dfrac{56}{88}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(4\dfrac{3}{12}+8\dfrac{1}{10}=\underline{\hspace{3cm}}\)12\dfrac{7}{20}\)
        \item \(\dfrac{36}{18}\div\dfrac{28}{8}=\underline{\hspace{3cm}}\)\dfrac{4}{7}\)
        \item \(\dfrac{72}{33}\div\dfrac{40}{15}=\underline{\hspace{3cm}}\)\dfrac{9}{11}\)
        \item \(\dfrac{36}{48}\div\dfrac{7}{35}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(\dfrac{90}{55}\div\dfrac{72}{44}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(1\dfrac{2}{7}\times1\dfrac{5}{90}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(9\dfrac{9}{12}+4\dfrac{3}{4}=\underline{\hspace{3cm}}\)14\dfrac{1}{2}\)
        \item \(6\dfrac{8}{12}-9\dfrac{3}{5}=\underline{\hspace{3cm}}\)16\dfrac{4}{15}\)
        \item \(5\dfrac{5}{6}-9\dfrac{2}{8}=\underline{\hspace{3cm}}\)15\dfrac{1}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 3. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(7\dfrac{1}{4}+2\dfrac{1}{5}=\underline{\hspace{3cm}}\)9\dfrac{9}{20}\)
        \item \(9\dfrac{1}{12}-4\dfrac{2}{4}=\underline{\hspace{3cm}}\)13\dfrac{7}{12}\)
        \item \(\dfrac{8}{64}\div\dfrac{40}{80}=\underline{\hspace{3cm}}\)\dfrac{1}{4}\)
        \item \(3\dfrac{5}{10}-8\dfrac{7}{8}=\underline{\hspace{3cm}}\)12\dfrac{3}{8}\)
        \item \(5\dfrac{6}{7}-9\dfrac{3}{6}=\underline{\hspace{3cm}}\)15\dfrac{5}{14}\)
        \item \(9\dfrac{8}{12}-7\dfrac{5}{6}=\underline{\hspace{3cm}}\)17\dfrac{1}{2}\)
        \item \(\dfrac{55}{5}\div\dfrac{99}{42}=\underline{\hspace{3cm}}\)\dfrac{14}{3}\)
        \item \(9\dfrac{3}{12}+7\dfrac{6}{9}=\underline{\hspace{3cm}}\)16\dfrac{11}{12}\)
        \item \(\dfrac{24}{48}\times7\dfrac{1}{3}=\underline{\hspace{3cm}}\)\dfrac{11}{3}\)
        \item \(7\dfrac{1}{4}+8\dfrac{5}{6}=\underline{\hspace{3cm}}\)16\dfrac{1}{12}\)
        \item \(2\dfrac{6}{9}-6\dfrac{2}{5}=\underline{\hspace{3cm}}\)9\dfrac{1}{15}\)
        \item \(\dfrac{66}{46}\div\dfrac{48}{92}=\underline{\hspace{3cm}}\)\dfrac{11}{4}\)
        \item \(6\dfrac{11}{12}+4\dfrac{2}{8}=\underline{\hspace{3cm}}\)11\dfrac{1}{6}\)
        \item \(9\dfrac{6}{12}-4\dfrac{7}{8}=\underline{\hspace{3cm}}\)14\dfrac{3}{8}\)
        \item \(7\dfrac{7}{10}-9\dfrac{4}{8}=\underline{\hspace{3cm}}\)17\dfrac{1}{5}\)
        \item \(\dfrac{15}{45}\div\dfrac{64}{60}=\underline{\hspace{3cm}}\)\dfrac{5}{16}\)
        \item \(3\dfrac{7}{17}\times\dfrac{3}{58}=\underline{\hspace{3cm}}\)\dfrac{3}{17}\)
        \item \(1\dfrac{17}{68}\times1\dfrac{5}{7}=\underline{\hspace{3cm}}\)\dfrac{15}{7}\)
        \item \(\dfrac{72}{21}\div\dfrac{56}{14}=\underline{\hspace{3cm}}\)\dfrac{6}{7}\)
        \item \(4\dfrac{3}{9}-7\dfrac{7}{12}=\underline{\hspace{3cm}}\)11\dfrac{11}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 4. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(4\dfrac{4}{6}+6\dfrac{8}{9}=\underline{\hspace{3cm}}\)11\dfrac{5}{9}\)
        \item \(3\dfrac{5}{10}+9\dfrac{1}{5}=\underline{\hspace{3cm}}\)12\dfrac{7}{10}\)
        \item \(4\dfrac{2}{10}+4\dfrac{4}{8}=\underline{\hspace{3cm}}\)8\dfrac{7}{10}\)
        \item \(5\dfrac{3}{12}-9\dfrac{9}{10}=\underline{\hspace{3cm}}\)15\dfrac{3}{20}\)
        \item \(8\dfrac{6}{10}-6\dfrac{3}{4}=\underline{\hspace{3cm}}\)15\dfrac{7}{20}\)
        \item \(2\dfrac{1}{4}+8\dfrac{3}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{2}\)
        \item \(6\dfrac{8}{9}+8\dfrac{10}{12}=\underline{\hspace{3cm}}\)15\dfrac{13}{18}\)
        \item \(\dfrac{27}{24}\times\dfrac{88}{66}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(5\dfrac{4}{12}-9\dfrac{2}{4}=\underline{\hspace{3cm}}\)14\dfrac{5}{6}\)
        \item \(7\dfrac{4}{6}-6\dfrac{1}{4}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(4\dfrac{10}{12}+5\dfrac{5}{6}=\underline{\hspace{3cm}}\)10\dfrac{2}{3}\)
        \item \(\dfrac{98}{78}\div\dfrac{21}{18}=\underline{\hspace{3cm}}\)\dfrac{14}{13}\)
        \item \(2\dfrac{7}{9}-9\dfrac{5}{6}=\underline{\hspace{3cm}}\)12\dfrac{11}{18}\)
        \item \(2\dfrac{4}{8}-8\dfrac{9}{12}=\underline{\hspace{3cm}}\)11\dfrac{1}{4}\)
        \item \(9\dfrac{3}{9}+9\dfrac{3}{4}=\underline{\hspace{3cm}}\)19\dfrac{1}{12}\)
        \item \(9\dfrac{6}{7}+6\dfrac{6}{12}=\underline{\hspace{3cm}}\)16\dfrac{5}{14}\)
        \item \(7\dfrac{3}{6}+6\dfrac{1}{4}=\underline{\hspace{3cm}}\)13\dfrac{3}{4}\)
        \item \(4\dfrac{2}{8}-6\dfrac{5}{12}=\underline{\hspace{3cm}}\)10\dfrac{2}{3}\)
        \item \(\dfrac{80}{16}\div\dfrac{25}{60}=\underline{\hspace{3cm}}\)\dfrac{12}{1}\)
        \item \(\dfrac{51}{9}\div\dfrac{74}{37}=\underline{\hspace{3cm}}\)\dfrac{17}{6}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 5. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(6\dfrac{6}{9}-2\dfrac{3}{4}=\underline{\hspace{3cm}}\)9\dfrac{5}{12}\)
        \item \(\dfrac{22}{9}\times\dfrac{35}{77}=\underline{\hspace{3cm}}\)\dfrac{10}{9}\)
        \item \(\dfrac{16}{12}\div\dfrac{8}{10}=\underline{\hspace{3cm}}\)\dfrac{5}{3}\)
        \item \(3\dfrac{1}{6}+3\dfrac{1}{10}=\underline{\hspace{3cm}}\)6\dfrac{4}{15}\)
        \item \(\dfrac{60}{35}\div\dfrac{24}{56}=\underline{\hspace{3cm}}\)\dfrac{4}{1}\)
        \item \(5\dfrac{8}{9}+4\dfrac{2}{4}=\underline{\hspace{3cm}}\)10\dfrac{7}{18}\)
        \item \(2\dfrac{4}{6}-6\dfrac{4}{8}=\underline{\hspace{3cm}}\)9\dfrac{1}{6}\)
        \item \(4\dfrac{3}{10}-8\dfrac{3}{4}=\underline{\hspace{3cm}}\)13\dfrac{1}{20}\)
        \item \(3\dfrac{5}{10}-5\dfrac{1}{6}=\underline{\hspace{3cm}}\)8\dfrac{2}{3}\)
        \item \(9\dfrac{1}{2}+7\dfrac{7}{9}=\underline{\hspace{3cm}}\)17\dfrac{5}{18}\)
        \item \(3\dfrac{2}{10}+7\dfrac{4}{8}=\underline{\hspace{3cm}}\)10\dfrac{7}{10}\)
        \item \(5\dfrac{6}{12}-6\dfrac{2}{4}=\underline{\hspace{3cm}}\)-12\)
        \item \(1\dfrac{20}{32}\times2\dfrac{10}{39}=\underline{\hspace{3cm}}\)\dfrac{11}{3}\)
        \item \(\dfrac{77}{99}\div\dfrac{12}{18}=\underline{\hspace{3cm}}\)\dfrac{7}{6}\)
        \item \(\dfrac{12}{21}\div\dfrac{32}{76}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(2\dfrac{2}{3}+3\dfrac{8}{10}=\underline{\hspace{3cm}}\)6\dfrac{7}{15}\)
        \item \(\dfrac{52}{90}\times\dfrac{80}{64}=\underline{\hspace{3cm}}\)\dfrac{13}{18}\)
        \item \(3\dfrac{1}{10}-6\dfrac{6}{12}=\underline{\hspace{3cm}}\)9\dfrac{3}{5}\)
        \item \(3\dfrac{4}{8}+2\dfrac{10}{12}=\underline{\hspace{3cm}}\)6\dfrac{1}{3}\)
        \item \(7\dfrac{3}{4}-5\dfrac{4}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 6. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(5\dfrac{3}{5}+3\dfrac{9}{12}=\underline{\hspace{3cm}}\)9\dfrac{7}{20}\)
        \item \(\dfrac{33}{44}\div\dfrac{72}{66}=\underline{\hspace{3cm}}\)\dfrac{11}{16}\)
        \item \(9\dfrac{4}{10}-9\dfrac{3}{12}=\underline{\hspace{3cm}}\)18\dfrac{13}{20}\)
        \item \(\dfrac{2}{4}\div\dfrac{21}{6}=\underline{\hspace{3cm}}\)\dfrac{1}{7}\)
        \item \(7\dfrac{3}{5}-5\dfrac{1}{2}=\underline{\hspace{3cm}}\)13\dfrac{1}{10}\)
        \item \(5\dfrac{1}{12}+6\dfrac{6}{8}=\underline{\hspace{3cm}}\)11\dfrac{5}{6}\)
        \item \(\dfrac{90}{45}\div\dfrac{21}{49}=\underline{\hspace{3cm}}\)\dfrac{14}{3}\)
        \item \(3\dfrac{5}{15}\times1\dfrac{8}{10}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(\dfrac{10}{33}\times\dfrac{99}{9}=\underline{\hspace{3cm}}\)\dfrac{10}{3}\)
        \item \(3\dfrac{5}{12}-3\dfrac{1}{6}=\underline{\hspace{3cm}}\)6\dfrac{7}{12}\)
        \item \(\dfrac{60}{50}\div\dfrac{30}{15}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(4\dfrac{2}{8}-6\dfrac{9}{10}=\underline{\hspace{3cm}}\)11\dfrac{3}{20}\)
        \item \(5\dfrac{2}{8}+7\dfrac{11}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{6}\)
        \item \(8\dfrac{6}{12}-8\dfrac{5}{9}=\underline{\hspace{3cm}}\)17\dfrac{1}{18}\)
        \item \(\dfrac{34}{2}\div\dfrac{50}{5}=\underline{\hspace{3cm}}\)\dfrac{17}{10}\)
        \item \(5\dfrac{1}{10}+2\dfrac{1}{2}=\underline{\hspace{3cm}}\)7\dfrac{3}{5}\)
        \item \(5\dfrac{3}{4}+5\dfrac{2}{5}=\underline{\hspace{3cm}}\)11\dfrac{3}{20}\)
        \item \(\dfrac{13}{26}\div\dfrac{12}{14}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(3\dfrac{8}{10}-6\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{20}\)
        \item \(\dfrac{57}{96}\times\dfrac{16}{3}=\underline{\hspace{3cm}}\)\dfrac{19}{6}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 7. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(4\dfrac{5}{12}+4\dfrac{5}{10}=\underline{\hspace{3cm}}\)8\dfrac{11}{12}\)
        \item \(\dfrac{92}{23}\div\dfrac{7}{14}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(4\dfrac{6}{10}+3\dfrac{1}{3}=\underline{\hspace{3cm}}\)7\dfrac{14}{15}\)
        \item \(\dfrac{9}{15}\div\dfrac{37}{74}=\underline{\hspace{3cm}}\)\dfrac{6}{5}\)
        \item \(4\dfrac{4}{9}+7\dfrac{4}{6}=\underline{\hspace{3cm}}\)12\dfrac{1}{9}\)
        \item \(8\dfrac{3}{5}-5\dfrac{1}{2}=\underline{\hspace{3cm}}\)14\dfrac{1}{10}\)
        \item \(\dfrac{20}{22}\div\dfrac{38}{57}=\underline{\hspace{3cm}}\)\dfrac{15}{11}\)
        \item \(6\dfrac{2}{9}+9\dfrac{10}{12}=\underline{\hspace{3cm}}\)16\dfrac{1}{18}\)
        \item \(2\dfrac{8}{10}+7\dfrac{8}{12}=\underline{\hspace{3cm}}\)10\dfrac{7}{15}\)
        \item \(5\dfrac{8}{10}+6\dfrac{2}{4}=\underline{\hspace{3cm}}\)12\dfrac{3}{10}\)
        \item \(4\dfrac{7}{12}+2\dfrac{3}{9}=\underline{\hspace{3cm}}\)6\dfrac{11}{12}\)
        \item \(8\dfrac{1}{3}-6\dfrac{9}{12}=\underline{\hspace{3cm}}\)15\dfrac{1}{12}\)
        \item \(7\dfrac{2}{8}+6\dfrac{6}{9}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(\dfrac{12}{96}\div\dfrac{9}{84}=\underline{\hspace{3cm}}\)\dfrac{7}{6}\)
        \item \(2\dfrac{3}{6}+2\dfrac{6}{8}=\underline{\hspace{3cm}}\)5\dfrac{1}{4}\)
        \item \(7\dfrac{3}{10}-9\dfrac{1}{5}=\underline{\hspace{3cm}}\)16\dfrac{1}{2}\)
        \item \(\dfrac{24}{90}\div\dfrac{48}{75}=\underline{\hspace{3cm}}\)\dfrac{5}{12}\)
        \item \(3\dfrac{1}{2}+2\dfrac{7}{9}=\underline{\hspace{3cm}}\)6\dfrac{5}{18}\)
        \item \(\dfrac{12}{14}\times\dfrac{11}{22}=\underline{\hspace{3cm}}\)\dfrac{3}{7}\)
        \item \(3\dfrac{7}{12}-2\dfrac{1}{3}=\underline{\hspace{3cm}}\)5\dfrac{11}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 8. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(2\dfrac{3}{4}\times\dfrac{45}{55}=\underline{\hspace{3cm}}\)\dfrac{9}{4}\)
        \item \(\dfrac{21}{49}\times\dfrac{84}{57}=\underline{\hspace{3cm}}\)\dfrac{12}{19}\)
        \item \(\dfrac{38}{19}\div\dfrac{8}{24}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(\dfrac{33}{45}\div\dfrac{33}{63}=\underline{\hspace{3cm}}\)\dfrac{7}{5}\)
        \item \(9\dfrac{1}{3}+6\dfrac{4}{9}=\underline{\hspace{3cm}}\)15\dfrac{7}{9}\)
        \item \(5\dfrac{7}{12}+2\dfrac{5}{10}=\underline{\hspace{3cm}}\)8\dfrac{1}{12}\)
        \item \(\dfrac{4}{6}\div\dfrac{33}{63}=\underline{\hspace{3cm}}\)\dfrac{14}{11}\)
        \item \(9\dfrac{1}{2}+5\dfrac{6}{8}=\underline{\hspace{3cm}}\)15\dfrac{1}{4}\)
        \item \(\dfrac{50}{85}\times1\dfrac{7}{14}=\underline{\hspace{3cm}}\)\dfrac{15}{17}\)
        \item \(\dfrac{63}{98}\times3\dfrac{17}{27}=\underline{\hspace{3cm}}\)\dfrac{7}{3}\)
        \item \(6\dfrac{5}{6}+7\dfrac{4}{12}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
        \item \(\dfrac{11}{62}\times1\dfrac{29}{33}=\underline{\hspace{3cm}}\)\dfrac{1}{3}\)
        \item \(\dfrac{18}{12}\times\dfrac{24}{99}=\underline{\hspace{3cm}}\)\dfrac{4}{11}\)
        \item \(\dfrac{55}{35}\times\dfrac{35}{99}=\underline{\hspace{3cm}}\)\dfrac{5}{9}\)
        \item \(6\dfrac{2}{9}+4\dfrac{5}{6}=\underline{\hspace{3cm}}\)11\dfrac{1}{18}\)
        \item \(9\dfrac{1}{5}+6\dfrac{6}{12}=\underline{\hspace{3cm}}\)15\dfrac{7}{10}\)
        \item \(5\dfrac{2}{12}+8\dfrac{5}{6}=\underline{\hspace{3cm}}\)-14\)
        \item \(\dfrac{52}{40}\div\dfrac{9}{30}=\underline{\hspace{3cm}}\)\dfrac{13}{3}\)
        \item \(6\dfrac{6}{10}+7\dfrac{1}{4}=\underline{\hspace{3cm}}\)13\dfrac{17}{20}\)
        \item \(9\dfrac{5}{10}-7\dfrac{2}{6}=\underline{\hspace{3cm}}\)16\dfrac{5}{6}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 9. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{46}{2}\times\dfrac{6}{46}=\underline{\hspace{3cm}}\)\dfrac{3}{1}\)
        \item \(9\dfrac{3}{5}-8\dfrac{2}{10}=\underline{\hspace{3cm}}\)17\dfrac{4}{5}\)
        \item \(\dfrac{84}{17}\times\dfrac{17}{35}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(\dfrac{30}{35}\div\dfrac{50}{35}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(\dfrac{45}{33}\div\dfrac{30}{14}=\underline{\hspace{3cm}}\)\dfrac{7}{11}\)
        \item \(\dfrac{36}{68}\div\dfrac{81}{45}=\underline{\hspace{3cm}}\)\dfrac{5}{17}\)
        \item \(\dfrac{26}{13}\div\dfrac{12}{84}=\underline{\hspace{3cm}}\)\dfrac{14}{1}\)
        \item \(\dfrac{20}{24}\div\dfrac{30}{4}=\underline{\hspace{3cm}}\)\dfrac{1}{9}\)
        \item \(2\dfrac{2}{6}-4\dfrac{4}{10}=\underline{\hspace{3cm}}\)6\dfrac{11}{15}\)
        \item \(\dfrac{54}{15}\times\dfrac{80}{16}=\underline{\hspace{3cm}}\)\dfrac{18}{1}\)
        \item \(\dfrac{80}{45}\div\dfrac{24}{36}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(7\dfrac{1}{2}-5\dfrac{4}{7}=\underline{\hspace{3cm}}\)13\dfrac{1}{14}\)
        \item \(6\dfrac{3}{4}+9\dfrac{2}{5}=\underline{\hspace{3cm}}\)16\dfrac{3}{20}\)
        \item \(6\dfrac{4}{8}-4\dfrac{3}{9}=\underline{\hspace{3cm}}\)10\dfrac{5}{6}\)
        \item \(7\dfrac{8}{12}+3\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{11}{12}\)
        \item \(6\dfrac{2}{4}+5\dfrac{3}{10}=\underline{\hspace{3cm}}\)11\dfrac{4}{5}\)
        \item \(2\dfrac{22}{28}\times\dfrac{19}{39}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(\dfrac{90}{45}\times\dfrac{56}{42}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(4\dfrac{4}{6}+8\dfrac{10}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{2}\)
        \item \(9\dfrac{2}{3}-4\dfrac{3}{9}=\underline{\hspace{3cm}}\)-14\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 10. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(2\dfrac{2}{5}+4\dfrac{3}{12}=\underline{\hspace{3cm}}\)6\dfrac{13}{20}\)
        \item \(\dfrac{5}{17}\times\dfrac{34}{55}=\underline{\hspace{3cm}}\)\dfrac{2}{11}\)
        \item \(3\dfrac{6}{9}+8\dfrac{2}{3}=\underline{\hspace{3cm}}\)12\dfrac{1}{3}\)
        \item \(9\dfrac{1}{2}+2\dfrac{10}{12}=\underline{\hspace{3cm}}\)12\dfrac{1}{3}\)
        \item \(2\dfrac{8}{10}-7\dfrac{2}{5}=\underline{\hspace{3cm}}\)10\dfrac{1}{5}\)
        \item \(5\dfrac{1}{2}-7\dfrac{7}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{12}\)
        \item \(2\dfrac{4}{16}\times1\dfrac{6}{90}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(5\dfrac{1}{3}-5\dfrac{4}{12}=\underline{\hspace{3cm}}\)10\dfrac{2}{3}\)
        \item \(6\dfrac{6}{8}+2\dfrac{1}{5}=\underline{\hspace{3cm}}\)8\dfrac{19}{20}\)
        \item \(\dfrac{26}{96}\times\dfrac{96}{32}=\underline{\hspace{3cm}}\)\dfrac{13}{16}\)
        \item \(2\dfrac{1}{5}+6\dfrac{8}{12}=\underline{\hspace{3cm}}\)8\dfrac{13}{15}\)
        \item \(\dfrac{65}{25}\div\dfrac{26}{10}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{52}{32}\div\dfrac{49}{56}=\underline{\hspace{3cm}}\)\dfrac{13}{7}\)
        \item \(\dfrac{24}{2}\div\dfrac{84}{7}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{36}{84}\div\dfrac{10}{42}=\underline{\hspace{3cm}}\)\dfrac{9}{5}\)
        \item \(3\dfrac{2}{4}-8\dfrac{1}{5}=\underline{\hspace{3cm}}\)11\dfrac{7}{10}\)
        \item \(9\dfrac{1}{6}-6\dfrac{2}{3}=\underline{\hspace{3cm}}\)15\dfrac{5}{6}\)
        \item \(7\dfrac{1}{4}+8\dfrac{1}{3}=\underline{\hspace{3cm}}\)15\dfrac{7}{12}\)
        \item \(6\dfrac{3}{4}-6\dfrac{8}{12}=\underline{\hspace{3cm}}\)13\dfrac{5}{12}\)
        \item \(\dfrac{38}{54}\div\dfrac{30}{81}=\underline{\hspace{3cm}}\)\dfrac{19}{10}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 11. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(2\dfrac{2}{3}+6\dfrac{4}{10}=\underline{\hspace{3cm}}\)9\dfrac{1}{15}\)
        \item \(8\dfrac{2}{8}+5\dfrac{5}{6}=\underline{\hspace{3cm}}\)14\dfrac{1}{12}\)
        \item \(\dfrac{25}{70}\div\dfrac{15}{6}=\underline{\hspace{3cm}}\)\dfrac{1}{7}\)
        \item \(9\dfrac{2}{9}+2\dfrac{1}{2}=\underline{\hspace{3cm}}\)11\dfrac{13}{18}\)
        \item \(1\dfrac{2}{4}\times\dfrac{24}{76}=\underline{\hspace{3cm}}\)\dfrac{9}{19}\)
        \item \(5\dfrac{4}{5}+2\dfrac{2}{8}=\underline{\hspace{3cm}}\)8\dfrac{1}{20}\)
        \item \(3\dfrac{4}{5}+8\dfrac{7}{10}=\underline{\hspace{3cm}}\)12\dfrac{1}{2}\)
        \item \(\dfrac{10}{18}\div\dfrac{40}{8}=\underline{\hspace{3cm}}\)\dfrac{1}{9}\)
        \item \(\dfrac{93}{62}\div\dfrac{99}{30}=\underline{\hspace{3cm}}\)\dfrac{5}{11}\)
        \item \(4\dfrac{6}{8}-6\dfrac{3}{5}=\underline{\hspace{3cm}}\)11\dfrac{7}{20}\)
        \item \(8\dfrac{7}{9}+3\dfrac{4}{8}=\underline{\hspace{3cm}}\)12\dfrac{5}{18}\)
        \item \(8\dfrac{6}{8}-8\dfrac{9}{12}=\underline{\hspace{3cm}}\)17\dfrac{1}{2}\)
        \item \(6\dfrac{2}{12}+5\dfrac{4}{9}=\underline{\hspace{3cm}}\)11\dfrac{11}{18}\)
        \item \(5\dfrac{1}{10}+6\dfrac{1}{2}=\underline{\hspace{3cm}}\)11\dfrac{3}{5}\)
        \item \(\dfrac{65}{80}\times\dfrac{76}{26}=\underline{\hspace{3cm}}\)\dfrac{19}{8}\)
        \item \(3\dfrac{3}{5}-2\dfrac{3}{10}=\underline{\hspace{3cm}}\)5\dfrac{9}{10}\)
        \item \(\dfrac{14}{36}\times\dfrac{15}{10}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(6\dfrac{2}{10}+4\dfrac{6}{12}=\underline{\hspace{3cm}}\)10\dfrac{7}{10}\)
        \item \(\dfrac{12}{72}\div\dfrac{15}{60}=\underline{\hspace{3cm}}\)\dfrac{2}{3}\)
        \item \(5\dfrac{3}{9}+8\dfrac{1}{12}=\underline{\hspace{3cm}}\)13\dfrac{5}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 12. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{87}{29}\div\dfrac{10}{8}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(1\dfrac{3}{44}\times\dfrac{8}{94}=\underline{\hspace{3cm}}\)\dfrac{1}{11}\)
        \item \(2\dfrac{2}{5}+5\dfrac{4}{6}=\underline{\hspace{3cm}}\)8\dfrac{1}{15}\)
        \item \(7\dfrac{4}{9}-4\dfrac{1}{6}=\underline{\hspace{3cm}}\)11\dfrac{11}{18}\)
        \item \(\dfrac{70}{45}\div\dfrac{34}{17}=\underline{\hspace{3cm}}\)\dfrac{7}{9}\)
        \item \(3\dfrac{3}{12}\times\dfrac{50}{75}=\underline{\hspace{3cm}}\)\dfrac{13}{6}\)
        \item \(\dfrac{34}{2}\div\dfrac{56}{8}=\underline{\hspace{3cm}}\)\dfrac{17}{7}\)
        \item \(6\dfrac{4}{10}+4\dfrac{2}{5}=\underline{\hspace{3cm}}\)10\dfrac{4}{5}\)
        \item \(\dfrac{10}{53}\times1\dfrac{18}{35}=\underline{\hspace{3cm}}\)\dfrac{2}{7}\)
        \item \(6\dfrac{8}{9}-8\dfrac{4}{6}=\underline{\hspace{3cm}}\)15\dfrac{5}{9}\)
        \item \(\dfrac{10}{28}\div\dfrac{90}{28}=\underline{\hspace{3cm}}\)\dfrac{1}{9}\)
        \item \(\dfrac{60}{84}\div\dfrac{25}{85}=\underline{\hspace{3cm}}\)\dfrac{17}{7}\)
        \item \(1\dfrac{12}{40}\times1\dfrac{9}{36}=\underline{\hspace{3cm}}\)\dfrac{13}{8}\)
        \item \(3\dfrac{1}{10}+6\dfrac{1}{6}=\underline{\hspace{3cm}}\)9\dfrac{4}{15}\)
        \item \(2\dfrac{7}{8}-7\dfrac{2}{4}=\underline{\hspace{3cm}}\)10\dfrac{3}{8}\)
        \item \(\dfrac{88}{12}\div\dfrac{88}{66}=\underline{\hspace{3cm}}\)\dfrac{11}{2}\)
        \item \(1\dfrac{20}{30}\times2\dfrac{21}{30}=\underline{\hspace{3cm}}\)\dfrac{9}{2}\)
        \item \(2\dfrac{4}{9}-8\dfrac{1}{2}=\underline{\hspace{3cm}}\)10\dfrac{17}{18}\)
        \item \(\dfrac{88}{30}\times\dfrac{2}{88}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
        \item \(\dfrac{2}{28}\div\dfrac{9}{42}=\underline{\hspace{3cm}}\)\dfrac{1}{3}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 13. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(3\dfrac{1}{2}-2\dfrac{5}{6}=\underline{\hspace{3cm}}\)6\dfrac{1}{3}\)
        \item \(6\dfrac{5}{10}-6\dfrac{4}{5}=\underline{\hspace{3cm}}\)13\dfrac{3}{10}\)
        \item \(\dfrac{77}{42}\div\dfrac{6}{2}=\underline{\hspace{3cm}}\)\dfrac{11}{18}\)
        \item \(\dfrac{29}{58}\div\dfrac{57}{19}=\underline{\hspace{3cm}}\)\dfrac{1}{6}\)
        \item \(8\dfrac{1}{3}-7\dfrac{2}{12}=\underline{\hspace{3cm}}\)15\dfrac{1}{2}\)
        \item \(9\dfrac{10}{12}-7\dfrac{4}{6}=\underline{\hspace{3cm}}\)17\dfrac{1}{2}\)
        \item \(\dfrac{60}{63}\times\dfrac{84}{60}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{6}{24}\div\dfrac{2}{3}=\underline{\hspace{3cm}}\)\dfrac{3}{8}\)
        \item \(\dfrac{12}{48}\times\dfrac{54}{24}=\underline{\hspace{3cm}}\)\dfrac{9}{16}\)
        \item \(\dfrac{2}{4}\div\dfrac{60}{75}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(9\dfrac{5}{6}-2\dfrac{1}{9}=\underline{\hspace{3cm}}\)11\dfrac{17}{18}\)
        \item \(\dfrac{27}{30}\div\dfrac{54}{78}=\underline{\hspace{3cm}}\)\dfrac{13}{10}\)
        \item \(1\dfrac{30}{66}\times1\dfrac{12}{54}=\underline{\hspace{3cm}}\)\dfrac{16}{9}\)
        \item \(3\dfrac{5}{10}+9\dfrac{5}{12}=\underline{\hspace{3cm}}\)12\dfrac{11}{12}\)
        \item \(4\dfrac{4}{5}+8\dfrac{3}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{20}\)
        \item \(9\dfrac{1}{5}+9\dfrac{3}{12}=\underline{\hspace{3cm}}\)18\dfrac{9}{20}\)
        \item \(\dfrac{25}{80}\times\dfrac{9}{15}=\underline{\hspace{3cm}}\)\dfrac{3}{16}\)
        \item \(\dfrac{12}{60}\div\dfrac{19}{95}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{36}{54}\times\dfrac{6}{68}=\underline{\hspace{3cm}}\)\dfrac{1}{17}\)
        \item \(\dfrac{2}{16}\div\dfrac{38}{32}=\underline{\hspace{3cm}}\)\dfrac{2}{19}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 14. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(2\dfrac{3}{9}-5\dfrac{3}{6}=\underline{\hspace{3cm}}\)7\dfrac{5}{6}\)
        \item \(\dfrac{16}{25}\times\dfrac{50}{34}=\underline{\hspace{3cm}}\)\dfrac{16}{17}\)
        \item \(5\dfrac{2}{12}-9\dfrac{3}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{2}\)
        \item \(6\dfrac{4}{6}-7\dfrac{6}{8}=\underline{\hspace{3cm}}\)14\dfrac{5}{12}\)
        \item \(2\dfrac{3}{5}+6\dfrac{9}{12}=\underline{\hspace{3cm}}\)9\dfrac{7}{20}\)
        \item \(\dfrac{38}{40}\div\dfrac{72}{80}=\underline{\hspace{3cm}}\)\dfrac{19}{18}\)
        \item \(3\dfrac{2}{4}-8\dfrac{4}{8}=\underline{\hspace{3cm}}\)-12\)
        \item \(\dfrac{38}{12}\div\dfrac{76}{24}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(5\dfrac{3}{5}+9\dfrac{3}{10}=\underline{\hspace{3cm}}\)14\dfrac{9}{10}\)
        \item \(9\dfrac{8}{12}-9\dfrac{6}{10}=\underline{\hspace{3cm}}\)19\dfrac{4}{15}\)
        \item \(1\dfrac{10}{54}\times\dfrac{72}{80}=\underline{\hspace{3cm}}\)\dfrac{16}{15}\)
        \item \(\dfrac{46}{45}\div\dfrac{69}{90}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{8}{98}\div\dfrac{72}{63}=\underline{\hspace{3cm}}\)\dfrac{1}{14}\)
        \item \(\dfrac{30}{58}\times\dfrac{58}{5}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(\dfrac{14}{4}\times\dfrac{32}{28}=\underline{\hspace{3cm}}\)\dfrac{4}{1}\)
        \item \(\dfrac{50}{60}\times\dfrac{76}{10}=\underline{\hspace{3cm}}\)\dfrac{19}{3}\)
        \item \(\dfrac{33}{75}\div\dfrac{66}{75}=\underline{\hspace{3cm}}\)\dfrac{1}{2}\)
        \item \(\dfrac{95}{20}\div\dfrac{25}{10}=\underline{\hspace{3cm}}\)\dfrac{19}{10}\)
        \item \(1\dfrac{13}{65}\times\dfrac{20}{24}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(5\dfrac{1}{9}-4\dfrac{8}{12}=\underline{\hspace{3cm}}\)9\dfrac{7}{9}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 15. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{48}{86}\times1\dfrac{4}{39}=\underline{\hspace{3cm}}\)\dfrac{8}{13}\)
        \item \(\dfrac{48}{10}\div\dfrac{28}{7}=\underline{\hspace{3cm}}\)\dfrac{6}{5}\)
        \item \(6\dfrac{6}{8}-6\dfrac{3}{4}=\underline{\hspace{3cm}}\)13\dfrac{1}{2}\)
        \item \(7\dfrac{1}{6}+3\dfrac{7}{12}=\underline{\hspace{3cm}}\)10\dfrac{3}{4}\)
        \item \(8\dfrac{8}{12}+4\dfrac{2}{3}=\underline{\hspace{3cm}}\)13\dfrac{1}{3}\)
        \item \(6\dfrac{1}{4}+7\dfrac{2}{6}=\underline{\hspace{3cm}}\)13\dfrac{7}{12}\)
        \item \(\dfrac{42}{12}\div\dfrac{98}{70}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(\dfrac{54}{27}\div\dfrac{20}{12}=\underline{\hspace{3cm}}\)\dfrac{6}{5}\)
        \item \(8\dfrac{2}{4}+6\dfrac{2}{6}=\underline{\hspace{3cm}}\)14\dfrac{5}{6}\)
        \item \(8\dfrac{4}{5}+4\dfrac{5}{10}=\underline{\hspace{3cm}}\)13\dfrac{3}{10}\)
        \item \(\dfrac{95}{76}\div\dfrac{55}{66}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(\dfrac{24}{78}\times4\dfrac{7}{21}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{54}{72}\div\dfrac{62}{93}=\underline{\hspace{3cm}}\)\dfrac{9}{8}\)
        \item \(7\dfrac{2}{8}+4\dfrac{3}{6}=\underline{\hspace{3cm}}\)11\dfrac{3}{4}\)
        \item \(9\dfrac{5}{8}+3\dfrac{1}{2}=\underline{\hspace{3cm}}\)13\dfrac{1}{8}\)
        \item \(4\dfrac{4}{6}-6\dfrac{4}{8}=\underline{\hspace{3cm}}\)11\dfrac{1}{6}\)
        \item \(2\dfrac{6}{8}+6\dfrac{1}{10}=\underline{\hspace{3cm}}\)8\dfrac{17}{20}\)
        \item \(1\dfrac{16}{40}\times\dfrac{15}{28}=\underline{\hspace{3cm}}\)\dfrac{3}{4}\)
        \item \(\dfrac{4}{3}\div\dfrac{36}{72}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(8\dfrac{9}{12}-9\dfrac{6}{8}=\underline{\hspace{3cm}}\)18\dfrac{1}{2}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 16. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(2\dfrac{2}{12}-3\dfrac{5}{9}=\underline{\hspace{3cm}}\)5\dfrac{13}{18}\)
        \item \(\dfrac{99}{11}\div\dfrac{10}{5}=\underline{\hspace{3cm}}\)\dfrac{9}{2}\)
        \item \(2\dfrac{3}{10}-6\dfrac{2}{8}=\underline{\hspace{3cm}}\)8\dfrac{11}{20}\)
        \item \(2\dfrac{5}{10}+5\dfrac{3}{4}=\underline{\hspace{3cm}}\)8\dfrac{1}{4}\)
        \item \(6\dfrac{4}{10}+6\dfrac{2}{3}=\underline{\hspace{3cm}}\)13\dfrac{1}{15}\)
        \item \(\dfrac{85}{51}\div\dfrac{9}{54}=\underline{\hspace{3cm}}\)\dfrac{10}{1}\)
        \item \(6\dfrac{1}{2}-6\dfrac{9}{10}=\underline{\hspace{3cm}}\)13\dfrac{2}{5}\)
        \item \(8\dfrac{1}{10}+5\dfrac{3}{5}=\underline{\hspace{3cm}}\)13\dfrac{7}{10}\)
        \item \(\dfrac{16}{68}\div\dfrac{19}{38}=\underline{\hspace{3cm}}\)\dfrac{8}{17}\)
        \item \(2\dfrac{14}{35}\times\dfrac{4}{6}=\underline{\hspace{3cm}}\)\dfrac{8}{5}\)
        \item \(\dfrac{70}{60}\times\dfrac{15}{5}=\underline{\hspace{3cm}}\)\dfrac{7}{2}\)
        \item \(\dfrac{90}{98}\div\dfrac{12}{98}=\underline{\hspace{3cm}}\)\dfrac{15}{2}\)
        \item \(9\dfrac{5}{9}+6\dfrac{5}{6}=\underline{\hspace{3cm}}\)16\dfrac{7}{18}\)
        \item \(\dfrac{78}{57}\div\dfrac{16}{38}=\underline{\hspace{3cm}}\)\dfrac{13}{4}\)
        \item \(\dfrac{21}{56}\div\dfrac{5}{80}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(5\dfrac{5}{10}-4\dfrac{2}{3}=\underline{\hspace{3cm}}\)10\dfrac{1}{6}\)
        \item \(1\dfrac{28}{42}\times1\dfrac{22}{50}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(\dfrac{60}{32}\times\dfrac{17}{51}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(7\dfrac{2}{4}+6\dfrac{2}{6}=\underline{\hspace{3cm}}\)13\dfrac{5}{6}\)
        \item \(2\dfrac{2}{4}+3\dfrac{2}{3}=\underline{\hspace{3cm}}\)6\dfrac{1}{6}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 17. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(1\dfrac{30}{39}\times\dfrac{12}{69}=\underline{\hspace{3cm}}\)\dfrac{4}{13}\)
        \item \(\dfrac{30}{72}\times5\dfrac{2}{10}=\underline{\hspace{3cm}}\)\dfrac{13}{6}\)
        \item \(\dfrac{28}{52}\div\dfrac{77}{11}=\underline{\hspace{3cm}}\)\dfrac{1}{13}\)
        \item \(1\dfrac{24}{54}\times\dfrac{25}{50}=\underline{\hspace{3cm}}\)\dfrac{13}{18}\)
        \item \(\dfrac{42}{63}\div\dfrac{3}{36}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(\dfrac{80}{56}\times\dfrac{11}{44}=\underline{\hspace{3cm}}\)\dfrac{5}{14}\)
        \item \(\dfrac{63}{66}\times\dfrac{42}{49}=\underline{\hspace{3cm}}\)\dfrac{9}{11}\)
        \item \(\dfrac{14}{21}\div\dfrac{21}{42}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{48}{88}\times\dfrac{85}{51}=\underline{\hspace{3cm}}\)\dfrac{10}{11}\)
        \item \(\dfrac{52}{72}\div\dfrac{26}{22}=\underline{\hspace{3cm}}\)\dfrac{11}{18}\)
        \item \(\dfrac{14}{63}\div\dfrac{18}{81}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{72}{12}\div\dfrac{88}{4}=\underline{\hspace{3cm}}\)\dfrac{3}{11}\)
        \item \(3\dfrac{18}{24}\times\dfrac{8}{30}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(3\dfrac{5}{10}-8\dfrac{1}{9}=\underline{\hspace{3cm}}\)11\dfrac{11}{18}\)
        \item \(\dfrac{18}{39}\div\dfrac{76}{78}=\underline{\hspace{3cm}}\)\dfrac{9}{19}\)
        \item \(5\dfrac{2}{6}+3\dfrac{2}{4}=\underline{\hspace{3cm}}\)8\dfrac{5}{6}\)
        \item \(\dfrac{3}{54}\div\dfrac{6}{63}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(9\dfrac{6}{12}-3\dfrac{5}{10}=\underline{\hspace{3cm}}\)-13\)
        \item \(2\dfrac{1}{28}\times1\dfrac{6}{18}=\underline{\hspace{3cm}}\)\dfrac{19}{7}\)
        \item \(4\dfrac{2}{7}-4\dfrac{3}{6}=\underline{\hspace{3cm}}\)8\dfrac{11}{14}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 18. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{70}{35}\div\dfrac{24}{12}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(1\dfrac{15}{20}\times1\dfrac{22}{42}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(\dfrac{10}{48}\times\dfrac{48}{22}=\underline{\hspace{3cm}}\)\dfrac{5}{11}\)
        \item \(\dfrac{6}{58}\times1\dfrac{13}{45}=\underline{\hspace{3cm}}\)\dfrac{2}{15}\)
        \item \(\dfrac{75}{54}\div\dfrac{60}{18}=\underline{\hspace{3cm}}\)\dfrac{5}{12}\)
        \item \(6\dfrac{6}{12}-5\dfrac{6}{10}=\underline{\hspace{3cm}}\)12\dfrac{1}{10}\)
        \item \(\dfrac{75}{11}\times\dfrac{22}{70}=\underline{\hspace{3cm}}\)\dfrac{15}{7}\)
        \item \(4\dfrac{1}{9}+5\dfrac{4}{12}=\underline{\hspace{3cm}}\)9\dfrac{4}{9}\)
        \item \(7\dfrac{3}{4}+2\dfrac{4}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(6\dfrac{6}{9}+6\dfrac{2}{4}=\underline{\hspace{3cm}}\)13\dfrac{1}{6}\)
        \item \(7\dfrac{5}{9}+7\dfrac{4}{6}=\underline{\hspace{3cm}}\)15\dfrac{2}{9}\)
        \item \(\dfrac{80}{57}\times\dfrac{39}{65}=\underline{\hspace{3cm}}\)\dfrac{16}{19}\)
        \item \(8\dfrac{8}{12}+3\dfrac{1}{4}=\underline{\hspace{3cm}}\)11\dfrac{11}{12}\)
        \item \(9\dfrac{1}{2}+5\dfrac{1}{9}=\underline{\hspace{3cm}}\)14\dfrac{11}{18}\)
        \item \(8\dfrac{2}{10}-3\dfrac{4}{5}=\underline{\hspace{3cm}}\)-12\)
        \item \(6\dfrac{8}{12}+2\dfrac{1}{4}=\underline{\hspace{3cm}}\)8\dfrac{11}{12}\)
        \item \(\dfrac{60}{28}\div\dfrac{54}{28}=\underline{\hspace{3cm}}\)\dfrac{10}{9}\)
        \item \(\dfrac{6}{3}\div\dfrac{27}{24}=\underline{\hspace{3cm}}\)\dfrac{16}{9}\)
        \item \(\dfrac{15}{85}\times\dfrac{29}{87}=\underline{\hspace{3cm}}\)\dfrac{1}{17}\)
        \item \(9\dfrac{5}{6}-4\dfrac{3}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 19. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(9\dfrac{3}{9}+3\dfrac{2}{4}=\underline{\hspace{3cm}}\)12\dfrac{5}{6}\)
        \item \(3\dfrac{10}{12}+4\dfrac{8}{9}=\underline{\hspace{3cm}}\)8\dfrac{13}{18}\)
        \item \(2\dfrac{2}{18}\times\dfrac{26}{38}=\underline{\hspace{3cm}}\)\dfrac{13}{9}\)
        \item \(\dfrac{54}{48}\div\dfrac{9}{80}=\underline{\hspace{3cm}}\)\dfrac{10}{1}\)
        \item \(6\dfrac{11}{12}-9\dfrac{3}{9}=\underline{\hspace{3cm}}\)16\dfrac{1}{4}\)
        \item \(\dfrac{22}{33}\div\dfrac{60}{95}=\underline{\hspace{3cm}}\)\dfrac{19}{18}\)
        \item \(8\dfrac{1}{2}-7\dfrac{3}{5}=\underline{\hspace{3cm}}\)16\dfrac{1}{10}\)
        \item \(\dfrac{55}{2}\times\dfrac{2}{88}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(\dfrac{52}{26}\times\dfrac{28}{98}=\underline{\hspace{3cm}}\)\dfrac{4}{7}\)
        \item \(\dfrac{27}{63}\times\dfrac{63}{33}=\underline{\hspace{3cm}}\)\dfrac{9}{11}\)
        \item \(\dfrac{33}{11}\times\dfrac{3}{9}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(5\dfrac{3}{10}+3\dfrac{3}{6}=\underline{\hspace{3cm}}\)8\dfrac{4}{5}\)
        \item \(\dfrac{27}{30}\times\dfrac{20}{51}=\underline{\hspace{3cm}}\)\dfrac{6}{17}\)
        \item \(\dfrac{20}{50}\div\dfrac{39}{15}=\underline{\hspace{3cm}}\)\dfrac{2}{13}\)
        \item \(\dfrac{45}{15}\div\dfrac{52}{65}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(\dfrac{10}{5}\div\dfrac{85}{15}=\underline{\hspace{3cm}}\)\dfrac{6}{17}\)
        \item \(4\dfrac{5}{10}+3\dfrac{3}{8}=\underline{\hspace{3cm}}\)7\dfrac{7}{8}\)
        \item \(\dfrac{8}{10}\times\dfrac{45}{72}=\underline{\hspace{3cm}}\)\dfrac{1}{2}\)
        \item \(9\dfrac{6}{10}-3\dfrac{3}{6}=\underline{\hspace{3cm}}\)13\dfrac{1}{10}\)
        \item \(\dfrac{66}{33}\times\dfrac{15}{54}=\underline{\hspace{3cm}}\)\dfrac{5}{9}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 20. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(9\dfrac{1}{2}-2\dfrac{7}{9}=\underline{\hspace{3cm}}\)12\dfrac{5}{18}\)
        \item \(3\dfrac{3}{9}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)7\dfrac{11}{15}\)
        \item \(\dfrac{28}{20}\times\dfrac{40}{28}=\underline{\hspace{3cm}}\)\dfrac{2}{1}\)
        \item \(\dfrac{42}{56}\div\dfrac{46}{69}=\underline{\hspace{3cm}}\)\dfrac{9}{8}\)
        \item \(5\dfrac{3}{12}+8\dfrac{4}{6}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(\dfrac{92}{26}\div\dfrac{46}{12}=\underline{\hspace{3cm}}\)\dfrac{12}{13}\)
        \item \(7\dfrac{5}{6}-9\dfrac{4}{8}=\underline{\hspace{3cm}}\)17\dfrac{1}{3}\)
        \item \(\dfrac{18}{99}\times\dfrac{37}{74}=\underline{\hspace{3cm}}\)\dfrac{1}{11}\)
        \item \(5\dfrac{2}{4}-4\dfrac{8}{9}=\underline{\hspace{3cm}}\)10\dfrac{7}{18}\)
        \item \(2\dfrac{4}{9}-5\dfrac{3}{6}=\underline{\hspace{3cm}}\)7\dfrac{17}{18}\)
        \item \(\dfrac{19}{57}\times\dfrac{36}{90}=\underline{\hspace{3cm}}\)\dfrac{2}{15}\)
        \item \(9\dfrac{3}{9}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)13\dfrac{11}{15}\)
        \item \(\dfrac{12}{28}\div\dfrac{20}{70}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(2\dfrac{3}{10}+4\dfrac{1}{2}=\underline{\hspace{3cm}}\)6\dfrac{4}{5}\)
        \item \(\dfrac{8}{15}\times4\dfrac{9}{18}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(\dfrac{9}{54}\div\dfrac{26}{91}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(4\dfrac{5}{10}+5\dfrac{1}{7}=\underline{\hspace{3cm}}\)9\dfrac{9}{14}\)
        \item \(1\dfrac{3}{17}\times\dfrac{17}{65}=\underline{\hspace{3cm}}\)\dfrac{4}{13}\)
        \item \(4\dfrac{6}{10}+4\dfrac{2}{5}=\underline{\hspace{3cm}}\)-9\)
        \item \(\dfrac{72}{29}\times\dfrac{58}{24}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 21. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(1\dfrac{8}{72}\times1\dfrac{10}{35}=\underline{\hspace{3cm}}\)\dfrac{10}{7}\)
        \item \(\dfrac{46}{8}\div\dfrac{69}{27}=\underline{\hspace{3cm}}\)\dfrac{9}{4}\)
        \item \(9\dfrac{3}{5}-4\dfrac{2}{6}=\underline{\hspace{3cm}}\)13\dfrac{14}{15}\)
        \item \(1\dfrac{17}{39}\times\dfrac{66}{77}=\underline{\hspace{3cm}}\)\dfrac{16}{13}\)
        \item \(2\dfrac{4}{20}\times\dfrac{25}{55}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(7\dfrac{2}{12}+4\dfrac{2}{8}=\underline{\hspace{3cm}}\)11\dfrac{5}{12}\)
        \item \(7\dfrac{10}{12}-7\dfrac{5}{6}=\underline{\hspace{3cm}}\)15\dfrac{2}{3}\)
        \item \(\dfrac{80}{85}\times\dfrac{5}{20}=\underline{\hspace{3cm}}\)\dfrac{4}{17}\)
        \item \(\dfrac{28}{60}\div\dfrac{84}{96}=\underline{\hspace{3cm}}\)\dfrac{8}{15}\)
        \item \(\dfrac{10}{4}\div\dfrac{69}{23}=\underline{\hspace{3cm}}\)\dfrac{5}{6}\)
        \item \(1\dfrac{40}{50}\times\dfrac{55}{66}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(8\dfrac{2}{3}\times1\dfrac{21}{42}=\underline{\hspace{3cm}}\)\dfrac{13}{1}\)
        \item \(\dfrac{28}{33}\times1\dfrac{3}{42}=\underline{\hspace{3cm}}\)\dfrac{10}{11}\)
        \item \(\dfrac{33}{96}\times\dfrac{96}{48}=\underline{\hspace{3cm}}\)\dfrac{11}{16}\)
        \item \(\dfrac{85}{25}\times\dfrac{50}{60}=\underline{\hspace{3cm}}\)\dfrac{17}{6}\)
        \item \(6\dfrac{2}{4}+5\dfrac{6}{8}=\underline{\hspace{3cm}}\)12\dfrac{1}{4}\)
        \item \(8\dfrac{2}{4}-9\dfrac{3}{7}=\underline{\hspace{3cm}}\)17\dfrac{13}{14}\)
        \item \(\dfrac{30}{42}\times5\dfrac{2}{8}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(3\dfrac{9}{12}-9\dfrac{5}{8}=\underline{\hspace{3cm}}\)13\dfrac{3}{8}\)
        \item \(5\dfrac{9}{12}+2\dfrac{2}{8}=\underline{\hspace{3cm}}\)-8\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 22. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{38}{19}\div\dfrac{76}{38}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(3\dfrac{2}{4}+3\dfrac{4}{12}=\underline{\hspace{3cm}}\)6\dfrac{5}{6}\)
        \item \(6\dfrac{9}{10}+2\dfrac{4}{8}=\underline{\hspace{3cm}}\)9\dfrac{2}{5}\)
        \item \(2\dfrac{6}{8}-7\dfrac{3}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{2}\)
        \item \(\dfrac{54}{90}\times\dfrac{40}{26}=\underline{\hspace{3cm}}\)\dfrac{12}{13}\)
        \item \(\dfrac{16}{20}\times\dfrac{70}{24}=\underline{\hspace{3cm}}\)\dfrac{7}{3}\)
        \item \(2\dfrac{6}{8}-9\dfrac{3}{5}=\underline{\hspace{3cm}}\)12\dfrac{7}{20}\)
        \item \(7\dfrac{5}{10}+2\dfrac{2}{7}=\underline{\hspace{3cm}}\)9\dfrac{11}{14}\)
        \item \(\dfrac{24}{45}\div\dfrac{32}{4}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
        \item \(2\dfrac{1}{3}+9\dfrac{11}{12}=\underline{\hspace{3cm}}\)12\dfrac{1}{4}\)
        \item \(5\dfrac{6}{12}-2\dfrac{6}{10}=\underline{\hspace{3cm}}\)8\dfrac{1}{10}\)
        \item \(\dfrac{42}{39}\div\dfrac{34}{17}=\underline{\hspace{3cm}}\)\dfrac{7}{13}\)
        \item \(\dfrac{51}{18}\div\dfrac{11}{66}=\underline{\hspace{3cm}}\)\dfrac{17}{1}\)
        \item \(7\dfrac{4}{6}-2\dfrac{6}{10}=\underline{\hspace{3cm}}\)10\dfrac{4}{15}\)
        \item \(7\dfrac{1}{6}-3\dfrac{1}{3}=\underline{\hspace{3cm}}\)10\dfrac{1}{2}\)
        \item \(9\dfrac{4}{6}+7\dfrac{2}{3}=\underline{\hspace{3cm}}\)17\dfrac{1}{3}\)
        \item \(2\dfrac{6}{8}-7\dfrac{6}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{4}\)
        \item \(4\dfrac{3}{5}-9\dfrac{2}{3}=\underline{\hspace{3cm}}\)14\dfrac{4}{15}\)
        \item \(\dfrac{77}{63}\div\dfrac{24}{27}=\underline{\hspace{3cm}}\)\dfrac{11}{8}\)
        \item \(\dfrac{98}{28}\times\dfrac{8}{20}=\underline{\hspace{3cm}}\)\dfrac{7}{5}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 23. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(8\dfrac{4}{5}-9\dfrac{1}{10}=\underline{\hspace{3cm}}\)17\dfrac{9}{10}\)
        \item \(\dfrac{30}{75}\div\dfrac{48}{50}=\underline{\hspace{3cm}}\)\dfrac{5}{12}\)
        \item \(1\dfrac{28}{49}\times\dfrac{64}{88}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(\dfrac{26}{52}\div\dfrac{15}{18}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(2\dfrac{11}{20}\times1\dfrac{38}{57}=\underline{\hspace{3cm}}\)\dfrac{17}{4}\)
        \item \(\dfrac{33}{55}\times\dfrac{50}{38}=\underline{\hspace{3cm}}\)\dfrac{15}{19}\)
        \item \(\dfrac{24}{77}\times3\dfrac{16}{24}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(9\dfrac{2}{5}-6\dfrac{3}{10}=\underline{\hspace{3cm}}\)15\dfrac{7}{10}\)
        \item \(4\dfrac{1}{5}-5\dfrac{3}{10}=\underline{\hspace{3cm}}\)9\dfrac{1}{2}\)
        \item \(3\dfrac{10}{12}+7\dfrac{5}{9}=\underline{\hspace{3cm}}\)11\dfrac{7}{18}\)
        \item \(\dfrac{46}{23}\times\dfrac{9}{81}=\underline{\hspace{3cm}}\)\dfrac{2}{9}\)
        \item \(\dfrac{40}{96}\times\dfrac{99}{66}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(\dfrac{65}{78}\times1\dfrac{22}{35}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(\dfrac{36}{57}\times\dfrac{57}{33}=\underline{\hspace{3cm}}\)\dfrac{12}{11}\)
        \item \(\dfrac{6}{15}\div\dfrac{4}{80}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(6\dfrac{3}{9}+7\dfrac{7}{12}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(5\dfrac{2}{12}-4\dfrac{6}{9}=\underline{\hspace{3cm}}\)9\dfrac{5}{6}\)
        \item \(\dfrac{16}{84}\div\dfrac{29}{87}=\underline{\hspace{3cm}}\)\dfrac{4}{7}\)
        \item \(9\dfrac{8}{10}-6\dfrac{3}{5}=\underline{\hspace{3cm}}\)16\dfrac{2}{5}\)
        \item \(\dfrac{36}{84}\times\dfrac{58}{87}=\underline{\hspace{3cm}}\)\dfrac{2}{7}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 24. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{20}{28}\div\dfrac{45}{72}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(\dfrac{69}{81}\times2\dfrac{8}{23}=\underline{\hspace{3cm}}\)\dfrac{2}{1}\)
        \item \(8\dfrac{4}{8}-7\dfrac{1}{6}=\underline{\hspace{3cm}}\)15\dfrac{2}{3}\)
        \item \(\dfrac{2}{60}\times\dfrac{72}{36}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
        \item \(\dfrac{75}{81}\div\dfrac{15}{81}=\underline{\hspace{3cm}}\)\dfrac{5}{1}\)
        \item \(1\dfrac{28}{32}\times1\dfrac{7}{21}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(7\dfrac{4}{8}+5\dfrac{4}{7}=\underline{\hspace{3cm}}\)13\dfrac{1}{14}\)
        \item \(\dfrac{70}{77}\times1\dfrac{12}{40}=\underline{\hspace{3cm}}\)\dfrac{13}{11}\)
        \item \(2\dfrac{1}{10}-6\dfrac{4}{5}=\underline{\hspace{3cm}}\)8\dfrac{9}{10}\)
        \item \(2\dfrac{5}{12}-4\dfrac{4}{8}=\underline{\hspace{3cm}}\)6\dfrac{11}{12}\)
        \item \(5\dfrac{1}{2}-4\dfrac{1}{6}=\underline{\hspace{3cm}}\)9\dfrac{2}{3}\)
        \item \(6\dfrac{3}{9}-4\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{7}{12}\)
        \item \(\dfrac{21}{6}\times\dfrac{22}{7}=\underline{\hspace{3cm}}\)\dfrac{11}{1}\)
        \item \(5\dfrac{1}{8}-8\dfrac{6}{12}=\underline{\hspace{3cm}}\)13\dfrac{5}{8}\)
        \item \(\dfrac{11}{2}\times\dfrac{10}{11}=\underline{\hspace{3cm}}\)\dfrac{5}{1}\)
        \item \(2\dfrac{3}{6}-9\dfrac{3}{8}=\underline{\hspace{3cm}}\)11\dfrac{7}{8}\)
        \item \(\dfrac{16}{10}\div\dfrac{56}{90}=\underline{\hspace{3cm}}\)\dfrac{18}{7}\)
        \item \(1\dfrac{11}{17}\times1\dfrac{4}{64}=\underline{\hspace{3cm}}\)\dfrac{7}{4}\)
        \item \(\dfrac{11}{88}\div\dfrac{4}{38}=\underline{\hspace{3cm}}\)\dfrac{19}{16}\)
        \item \(\dfrac{18}{28}\div\dfrac{24}{42}=\underline{\hspace{3cm}}\)\dfrac{9}{8}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 25. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(8\dfrac{2}{3}-5\dfrac{6}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{3}\)
        \item \(7\dfrac{11}{12}-6\dfrac{2}{8}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
        \item \(4\dfrac{5}{6}+5\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(\dfrac{15}{56}\div\dfrac{60}{48}=\underline{\hspace{3cm}}\)\dfrac{3}{14}\)
        \item \(\dfrac{72}{88}\div\dfrac{23}{46}=\underline{\hspace{3cm}}\)\dfrac{18}{11}\)
        \item \(\dfrac{72}{86}\times7\dfrac{2}{12}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(2\dfrac{5}{20}\times1\dfrac{18}{27}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(\dfrac{48}{27}\times\dfrac{27}{16}=\underline{\hspace{3cm}}\)\dfrac{3}{1}\)
        \item \(6\dfrac{2}{5}-7\dfrac{2}{4}=\underline{\hspace{3cm}}\)13\dfrac{9}{10}\)
        \item \(9\dfrac{7}{9}+5\dfrac{2}{12}=\underline{\hspace{3cm}}\)14\dfrac{17}{18}\)
        \item \(\dfrac{66}{14}\times\dfrac{98}{66}=\underline{\hspace{3cm}}\)\dfrac{7}{1}\)
        \item \(1\dfrac{8}{40}\times1\dfrac{25}{30}=\underline{\hspace{3cm}}\)\dfrac{11}{5}\)
        \item \(4\dfrac{1}{2}+7\dfrac{2}{7}=\underline{\hspace{3cm}}\)11\dfrac{11}{14}\)
        \item \(7\dfrac{6}{7}-6\dfrac{3}{6}=\underline{\hspace{3cm}}\)14\dfrac{5}{14}\)
        \item \(3\dfrac{4}{5}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)8\dfrac{1}{5}\)
        \item \(6\dfrac{9}{10}+2\dfrac{10}{12}=\underline{\hspace{3cm}}\)9\dfrac{11}{15}\)
        \item \(5\dfrac{6}{10}+3\dfrac{4}{8}=\underline{\hspace{3cm}}\)9\dfrac{1}{10}\)
        \item \(4\dfrac{1}{4}+4\dfrac{7}{10}=\underline{\hspace{3cm}}\)8\dfrac{19}{20}\)
        \item \(\dfrac{36}{6}\div\dfrac{33}{2}=\underline{\hspace{3cm}}\)\dfrac{4}{11}\)
        \item \(5\dfrac{3}{6}-7\dfrac{5}{7}=\underline{\hspace{3cm}}\)13\dfrac{3}{14}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 26. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(7\dfrac{5}{6}+6\dfrac{3}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
        \item \(2\dfrac{10}{12}-8\dfrac{3}{10}=\underline{\hspace{3cm}}\)11\dfrac{2}{15}\)
        \item \(\dfrac{9}{78}\div\dfrac{66}{88}=\underline{\hspace{3cm}}\)\dfrac{2}{13}\)
        \item \(\dfrac{98}{24}\div\dfrac{14}{6}=\underline{\hspace{3cm}}\)\dfrac{7}{4}\)
        \item \(2\dfrac{1}{9}+2\dfrac{1}{2}=\underline{\hspace{3cm}}\)4\dfrac{11}{18}\)
        \item \(\dfrac{32}{80}\times2\dfrac{12}{14}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(\dfrac{98}{91}\times\dfrac{13}{63}=\underline{\hspace{3cm}}\)\dfrac{2}{9}\)
        \item \(\dfrac{39}{78}\div\dfrac{30}{56}=\underline{\hspace{3cm}}\)\dfrac{14}{15}\)
        \item \(5\dfrac{11}{12}-7\dfrac{4}{8}=\underline{\hspace{3cm}}\)13\dfrac{5}{12}\)
        \item \(\dfrac{65}{13}\div\dfrac{70}{22}=\underline{\hspace{3cm}}\)\dfrac{11}{7}\)
        \item \(\dfrac{48}{40}\div\dfrac{6}{70}=\underline{\hspace{3cm}}\)\dfrac{14}{1}\)
        \item \(3\dfrac{11}{12}-6\dfrac{3}{9}=\underline{\hspace{3cm}}\)10\dfrac{1}{4}\)
        \item \(\dfrac{12}{78}\times1\dfrac{19}{38}=\underline{\hspace{3cm}}\)\dfrac{3}{13}\)
        \item \(\dfrac{35}{70}\div\dfrac{81}{72}=\underline{\hspace{3cm}}\)\dfrac{4}{9}\)
        \item \(7\dfrac{3}{5}-7\dfrac{1}{4}=\underline{\hspace{3cm}}\)14\dfrac{17}{20}\)
        \item \(5\dfrac{8}{9}+9\dfrac{1}{3}=\underline{\hspace{3cm}}\)15\dfrac{2}{9}\)
        \item \(3\dfrac{3}{4}+8\dfrac{1}{3}=\underline{\hspace{3cm}}\)12\dfrac{1}{12}\)
        \item \(\dfrac{48}{8}\times\dfrac{40}{96}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(4\dfrac{3}{6}+6\dfrac{7}{8}=\underline{\hspace{3cm}}\)11\dfrac{3}{8}\)
        \item \(3\dfrac{11}{12}+5\dfrac{3}{4}=\underline{\hspace{3cm}}\)9\dfrac{2}{3}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 27. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{51}{12}\div\dfrac{85}{20}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(6\dfrac{1}{9}-7\dfrac{4}{12}=\underline{\hspace{3cm}}\)13\dfrac{4}{9}\)
        \item \(7\dfrac{5}{6}-8\dfrac{4}{12}=\underline{\hspace{3cm}}\)16\dfrac{1}{6}\)
        \item \(4\dfrac{2}{6}-5\dfrac{10}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{6}\)
        \item \(\dfrac{8}{96}\div\dfrac{10}{20}=\underline{\hspace{3cm}}\)\dfrac{1}{6}\)
        \item \(1\dfrac{17}{39}\times\dfrac{27}{84}=\underline{\hspace{3cm}}\)\dfrac{6}{13}\)
        \item \(2\dfrac{1}{6}-7\dfrac{2}{3}=\underline{\hspace{3cm}}\)9\dfrac{5}{6}\)
        \item \(3\dfrac{6}{7}-8\dfrac{5}{10}=\underline{\hspace{3cm}}\)12\dfrac{5}{14}\)
        \item \(9\dfrac{2}{8}-9\dfrac{1}{12}=\underline{\hspace{3cm}}\)18\dfrac{1}{3}\)
        \item \(2\dfrac{1}{9}+3\dfrac{10}{12}=\underline{\hspace{3cm}}\)5\dfrac{17}{18}\)
        \item \(5\dfrac{4}{8}+5\dfrac{2}{7}=\underline{\hspace{3cm}}\)10\dfrac{11}{14}\)
        \item \(\dfrac{27}{36}\times\dfrac{2}{18}=\underline{\hspace{3cm}}\)\dfrac{1}{12}\)
        \item \(4\dfrac{10}{12}+6\dfrac{3}{6}=\underline{\hspace{3cm}}\)11\dfrac{1}{3}\)
        \item \(8\dfrac{3}{6}+5\dfrac{3}{9}=\underline{\hspace{3cm}}\)13\dfrac{5}{6}\)
        \item \(\dfrac{57}{99}\div\dfrac{9}{33}=\underline{\hspace{3cm}}\)\dfrac{19}{9}\)
        \item \(\dfrac{10}{6}\div\dfrac{77}{21}=\underline{\hspace{3cm}}\)\dfrac{5}{11}\)
        \item \(1\dfrac{10}{34}\times\dfrac{16}{22}=\underline{\hspace{3cm}}\)\dfrac{16}{17}\)
        \item \(2\dfrac{9}{12}-3\dfrac{3}{5}=\underline{\hspace{3cm}}\)6\dfrac{7}{20}\)
        \item \(9\dfrac{7}{9}\times\dfrac{9}{96}=\underline{\hspace{3cm}}\)\dfrac{11}{12}\)
        \item \(9\dfrac{1}{3}+9\dfrac{1}{9}=\underline{\hspace{3cm}}\)18\dfrac{4}{9}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 28. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{72}{20}\div\dfrac{12}{50}=\underline{\hspace{3cm}}\)\dfrac{15}{1}\)
        \item \(4\dfrac{2}{4}+7\dfrac{4}{7}=\underline{\hspace{3cm}}\)12\dfrac{1}{14}\)
        \item \(5\dfrac{3}{9}+2\dfrac{4}{5}=\underline{\hspace{3cm}}\)8\dfrac{2}{15}\)
        \item \(\dfrac{99}{51}\div\dfrac{75}{85}=\underline{\hspace{3cm}}\)\dfrac{11}{5}\)
        \item \(7\dfrac{3}{6}-2\dfrac{7}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(2\dfrac{3}{12}+6\dfrac{5}{8}=\underline{\hspace{3cm}}\)8\dfrac{7}{8}\)
        \item \(\dfrac{12}{20}\times\dfrac{68}{24}=\underline{\hspace{3cm}}\)\dfrac{17}{10}\)
        \item \(2\dfrac{9}{12}-3\dfrac{3}{10}=\underline{\hspace{3cm}}\)6\dfrac{1}{20}\)
        \item \(\dfrac{26}{16}\div\dfrac{29}{58}=\underline{\hspace{3cm}}\)\dfrac{13}{4}\)
        \item \(3\dfrac{6}{8}-4\dfrac{6}{9}=\underline{\hspace{3cm}}\)8\dfrac{5}{12}\)
        \item \(4\dfrac{6}{8}+4\dfrac{8}{12}=\underline{\hspace{3cm}}\)9\dfrac{5}{12}\)
        \item \(3\dfrac{2}{4}-2\dfrac{8}{12}=\underline{\hspace{3cm}}\)6\dfrac{1}{6}\)
        \item \(\dfrac{72}{15}\div\dfrac{96}{50}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(6\dfrac{1}{2}+2\dfrac{2}{8}=\underline{\hspace{3cm}}\)8\dfrac{3}{4}\)
        \item \(6\dfrac{5}{12}-9\dfrac{5}{10}=\underline{\hspace{3cm}}\)15\dfrac{11}{12}\)
        \item \(6\dfrac{3}{8}+8\dfrac{1}{2}=\underline{\hspace{3cm}}\)14\dfrac{7}{8}\)
        \item \(2\dfrac{6}{10}-2\dfrac{9}{12}=\underline{\hspace{3cm}}\)5\dfrac{7}{20}\)
        \item \(1\dfrac{12}{18}\times\dfrac{27}{80}=\underline{\hspace{3cm}}\)\dfrac{9}{16}\)
        \item \(9\dfrac{1}{2}+7\dfrac{4}{7}=\underline{\hspace{3cm}}\)17\dfrac{1}{14}\)
        \item \(\dfrac{21}{35}\div\dfrac{72}{8}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 29. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{27}{18}\div\dfrac{66}{76}=\underline{\hspace{3cm}}\)\dfrac{19}{11}\)
        \item \(\dfrac{10}{68}\times\dfrac{68}{85}=\underline{\hspace{3cm}}\)\dfrac{2}{17}\)
        \item \(5\dfrac{1}{3}+5\dfrac{10}{12}=\underline{\hspace{3cm}}\)11\dfrac{1}{6}\)
        \item \(7\dfrac{3}{4}-4\dfrac{4}{8}=\underline{\hspace{3cm}}\)12\dfrac{1}{4}\)
        \item \(\dfrac{12}{15}\times1\dfrac{9}{66}=\underline{\hspace{3cm}}\)\dfrac{10}{11}\)
        \item \(\dfrac{12}{32}\times\dfrac{52}{12}=\underline{\hspace{3cm}}\)\dfrac{13}{8}\)
        \item \(6\dfrac{3}{6}-2\dfrac{3}{12}=\underline{\hspace{3cm}}\)8\dfrac{3}{4}\)
        \item \(2\dfrac{4}{7}-2\dfrac{5}{10}=\underline{\hspace{3cm}}\)5\dfrac{1}{14}\)
        \item \(\dfrac{51}{27}\div\dfrac{80}{45}=\underline{\hspace{3cm}}\)\dfrac{17}{16}\)
        \item \(9\dfrac{3}{6}+7\dfrac{10}{12}=\underline{\hspace{3cm}}\)17\dfrac{1}{3}\)
        \item \(\dfrac{60}{25}\div\dfrac{38}{10}=\underline{\hspace{3cm}}\)\dfrac{12}{19}\)
        \item \(4\dfrac{8}{12}-8\dfrac{2}{6}=\underline{\hspace{3cm}}\)-13\)
        \item \(3\dfrac{5}{9}+4\dfrac{2}{12}=\underline{\hspace{3cm}}\)7\dfrac{13}{18}\)
        \item \(\dfrac{15}{54}\div\dfrac{40}{12}=\underline{\hspace{3cm}}\)\dfrac{1}{12}\)
        \item \(9\dfrac{2}{9}-9\dfrac{3}{6}=\underline{\hspace{3cm}}\)18\dfrac{13}{18}\)
        \item \(2\dfrac{16}{28}\times2\dfrac{7}{21}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(7\dfrac{8}{12}-3\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{11}{12}\)
        \item \(\dfrac{7}{97}\times2\dfrac{13}{42}=\underline{\hspace{3cm}}\)\dfrac{1}{6}\)
        \item \(\dfrac{35}{30}\div\dfrac{95}{30}=\underline{\hspace{3cm}}\)\dfrac{7}{19}\)
        \item \(\dfrac{56}{14}\times\dfrac{90}{24}=\underline{\hspace{3cm}}\)\dfrac{15}{1}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 30. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}
        \item \(\dfrac{42}{60}\times1\dfrac{6}{14}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(2\dfrac{4}{7}+6\dfrac{2}{4}=\underline{\hspace{3cm}}\)9\dfrac{1}{14}\)
        \item \(\dfrac{6}{96}\div\dfrac{45}{90}=\underline{\hspace{3cm}}\)\dfrac{1}{8}\)
        \item \(8\dfrac{6}{10}-4\dfrac{9}{12}=\underline{\hspace{3cm}}\)13\dfrac{7}{20}\)
        \item \(5\dfrac{7}{12}-3\dfrac{2}{3}=\underline{\hspace{3cm}}\)9\dfrac{1}{4}\)
        \item \(6\dfrac{6}{8}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)11\dfrac{3}{20}\)
        \item \(8\dfrac{1}{4}+9\dfrac{2}{10}=\underline{\hspace{3cm}}\)17\dfrac{9}{20}\)
        \item \(1\dfrac{12}{20}\times1\dfrac{6}{84}=\underline{\hspace{3cm}}\)\dfrac{12}{7}\)
        \item \(\dfrac{64}{80}\times\dfrac{34}{68}=\underline{\hspace{3cm}}\)\dfrac{2}{5}\)
        \item \(\dfrac{49}{21}\div\dfrac{60}{30}=\underline{\hspace{3cm}}\)\dfrac{7}{6}\)
        \item \(5\dfrac{5}{8}+4\dfrac{6}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{8}\)
        \item \(8\dfrac{5}{10}-4\dfrac{2}{5}=\underline{\hspace{3cm}}\)12\dfrac{9}{10}\)
        \item \(\dfrac{29}{58}\times\dfrac{40}{6}=\underline{\hspace{3cm}}\)\dfrac{10}{3}\)
        \item \(\dfrac{45}{18}\div\dfrac{90}{12}=\underline{\hspace{3cm}}\)\dfrac{1}{3}\)
        \item \(\dfrac{76}{98}\div\dfrac{64}{98}=\underline{\hspace{3cm}}\)\dfrac{19}{16}\)
        \item \(6\dfrac{3}{9}-3\dfrac{3}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(\dfrac{72}{56}\div\dfrac{60}{28}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(\dfrac{58}{72}\times\dfrac{78}{87}=\underline{\hspace{3cm}}\)\dfrac{13}{18}\)
        \item \(\dfrac{88}{72}\times\dfrac{63}{99}=\underline{\hspace{3cm}}\)\dfrac{7}{9}\)
        \item \(2\dfrac{1}{4}-8\dfrac{4}{5}=\underline{\hspace{3cm}}\)11\dfrac{1}{20}\)
    \end{enumerate}
\end{multicols}

\newpage

\begin{figure}[ht!]
\vspace{-23mm}\hspace*{-23mm}\includegraphics[scale=0.9]{Logo.jpg}
\end{figure}

\vspace{-15mm}\hspace*{-10mm}\begingroup
\centering
\LARGE Fraction Arithmetic (General) \\[0.5em]
\endgroup

\subsection{Exercise 31. Calculate and express the answer in simplest forms.}
\begin{multicols}{2}
    \begin{enumerate}[label=\arabic*)]
        \setlength\itemsep{2em}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\newpage

\newgeometry{
 a4paper,
 total={170mm,257mm},
 left=15mm,
 top=20mm,
 bottom=20mm,
 right=15mm
 }
\fontsize{10pt}{10pt}\selectfont

\section{Fraction Arithmetic (General) Answer Key}
\textbf{p1}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(5\dfrac{7}{13}\times1\dfrac{15}{24}=\underline{\hspace{3cm}}\)\dfrac{9}{1}\)
        \item \(1\dfrac{8}{9}\times1\dfrac{13}{17}=\underline{\hspace{3cm}}\)\dfrac{10}{3}\)
        \item \(1\dfrac{6}{54}\times\dfrac{9}{85}=\underline{\hspace{3cm}}\)\dfrac{2}{17}\)
        \item \(\dfrac{36}{81}\div\dfrac{7}{84}=\underline{\hspace{3cm}}\)\dfrac{16}{3}\)
        \item \(6\dfrac{9}{12}+3\dfrac{1}{3}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(5\dfrac{2}{11}\times\dfrac{9}{27}=\underline{\hspace{3cm}}\)\dfrac{19}{11}\)
        \item \(\dfrac{21}{45}\div\dfrac{56}{72}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(1\dfrac{1}{15}\times7\dfrac{4}{8}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(\dfrac{10}{52}\times3\dfrac{2}{8}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(8\dfrac{2}{8}-9\dfrac{8}{12}=\underline{\hspace{3cm}}\)17\dfrac{11}{12}\)
        \item \(7\dfrac{9}{10}+9\dfrac{2}{8}=\underline{\hspace{3cm}}\)17\dfrac{3}{20}\)
        \item \(3\dfrac{4}{6}-9\dfrac{5}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{12}\)
        \item \(\dfrac{28}{90}\times\dfrac{21}{14}=\underline{\hspace{3cm}}\)\dfrac{7}{15}\)
        \item \(2\dfrac{18}{19}\times2\dfrac{25}{35}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(8\dfrac{7}{8}-5\dfrac{3}{12}=\underline{\hspace{3cm}}\)14\dfrac{1}{8}\)
        \item \(1\dfrac{2}{6}\times2\dfrac{2}{20}=\underline{\hspace{3cm}}\)\dfrac{14}{5}\)
        \item \(\dfrac{10}{72}\times2\dfrac{24}{30}=\underline{\hspace{3cm}}\)\dfrac{7}{18}\)
        \item \(\dfrac{23}{34}\times1\dfrac{3}{69}=\underline{\hspace{3cm}}\)\dfrac{12}{17}\)
        \item \(\dfrac{45}{36}\div\dfrac{18}{8}=\underline{\hspace{3cm}}\)\dfrac{5}{9}\)
        \item \(4\dfrac{6}{9}-7\dfrac{1}{4}=\underline{\hspace{3cm}}\)11\dfrac{11}{12}\)
    \end{enumerate}
\end{multicols}

\textbf{p2}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(6\dfrac{3}{4}-8\dfrac{1}{10}=\underline{\hspace{3cm}}\)14\dfrac{17}{20}\)
        \item \(2\dfrac{4}{8}-8\dfrac{4}{9}=\underline{\hspace{3cm}}\)10\dfrac{17}{18}\)
        \item \(\dfrac{45}{20}\div\dfrac{66}{16}=\underline{\hspace{3cm}}\)\dfrac{6}{11}\)
        \item \(3\dfrac{8}{10}-2\dfrac{4}{6}=\underline{\hspace{3cm}}\)6\dfrac{7}{15}\)
        \item \(9\dfrac{1}{6}-5\dfrac{1}{12}=\underline{\hspace{3cm}}\)14\dfrac{1}{4}\)
        \item \(\dfrac{26}{32}\div\dfrac{26}{16}=\underline{\hspace{3cm}}\)\dfrac{1}{2}\)
        \item \(5\dfrac{4}{6}+7\dfrac{2}{9}=\underline{\hspace{3cm}}\)12\dfrac{8}{9}\)
        \item \(6\dfrac{1}{2}-2\dfrac{3}{5}=\underline{\hspace{3cm}}\)9\dfrac{1}{10}\)
        \item \(\dfrac{24}{72}\times\dfrac{40}{30}=\underline{\hspace{3cm}}\)\dfrac{4}{9}\)
        \item \(9\dfrac{1}{2}-7\dfrac{1}{7}=\underline{\hspace{3cm}}\)16\dfrac{9}{14}\)
        \item \(\dfrac{48}{66}\div\dfrac{56}{88}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(4\dfrac{3}{12}+8\dfrac{1}{10}=\underline{\hspace{3cm}}\)12\dfrac{7}{20}\)
        \item \(\dfrac{36}{18}\div\dfrac{28}{8}=\underline{\hspace{3cm}}\)\dfrac{4}{7}\)
        \item \(\dfrac{72}{33}\div\dfrac{40}{15}=\underline{\hspace{3cm}}\)\dfrac{9}{11}\)
        \item \(\dfrac{36}{48}\div\dfrac{7}{35}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(\dfrac{90}{55}\div\dfrac{72}{44}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(1\dfrac{2}{7}\times1\dfrac{5}{90}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(9\dfrac{9}{12}+4\dfrac{3}{4}=\underline{\hspace{3cm}}\)14\dfrac{1}{2}\)
        \item \(6\dfrac{8}{12}-9\dfrac{3}{5}=\underline{\hspace{3cm}}\)16\dfrac{4}{15}\)
        \item \(5\dfrac{5}{6}-9\dfrac{2}{8}=\underline{\hspace{3cm}}\)15\dfrac{1}{12}\)
    \end{enumerate}
\end{multicols}

\textbf{p3}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(7\dfrac{1}{4}+2\dfrac{1}{5}=\underline{\hspace{3cm}}\)9\dfrac{9}{20}\)
        \item \(9\dfrac{1}{12}-4\dfrac{2}{4}=\underline{\hspace{3cm}}\)13\dfrac{7}{12}\)
        \item \(\dfrac{8}{64}\div\dfrac{40}{80}=\underline{\hspace{3cm}}\)\dfrac{1}{4}\)
        \item \(3\dfrac{5}{10}-8\dfrac{7}{8}=\underline{\hspace{3cm}}\)12\dfrac{3}{8}\)
        \item \(5\dfrac{6}{7}-9\dfrac{3}{6}=\underline{\hspace{3cm}}\)15\dfrac{5}{14}\)
        \item \(9\dfrac{8}{12}-7\dfrac{5}{6}=\underline{\hspace{3cm}}\)17\dfrac{1}{2}\)
        \item \(\dfrac{55}{5}\div\dfrac{99}{42}=\underline{\hspace{3cm}}\)\dfrac{14}{3}\)
        \item \(9\dfrac{3}{12}+7\dfrac{6}{9}=\underline{\hspace{3cm}}\)16\dfrac{11}{12}\)
        \item \(\dfrac{24}{48}\times7\dfrac{1}{3}=\underline{\hspace{3cm}}\)\dfrac{11}{3}\)
        \item \(7\dfrac{1}{4}+8\dfrac{5}{6}=\underline{\hspace{3cm}}\)16\dfrac{1}{12}\)
        \item \(2\dfrac{6}{9}-6\dfrac{2}{5}=\underline{\hspace{3cm}}\)9\dfrac{1}{15}\)
        \item \(\dfrac{66}{46}\div\dfrac{48}{92}=\underline{\hspace{3cm}}\)\dfrac{11}{4}\)
        \item \(6\dfrac{11}{12}+4\dfrac{2}{8}=\underline{\hspace{3cm}}\)11\dfrac{1}{6}\)
        \item \(9\dfrac{6}{12}-4\dfrac{7}{8}=\underline{\hspace{3cm}}\)14\dfrac{3}{8}\)
        \item \(7\dfrac{7}{10}-9\dfrac{4}{8}=\underline{\hspace{3cm}}\)17\dfrac{1}{5}\)
        \item \(\dfrac{15}{45}\div\dfrac{64}{60}=\underline{\hspace{3cm}}\)\dfrac{5}{16}\)
        \item \(3\dfrac{7}{17}\times\dfrac{3}{58}=\underline{\hspace{3cm}}\)\dfrac{3}{17}\)
        \item \(1\dfrac{17}{68}\times1\dfrac{5}{7}=\underline{\hspace{3cm}}\)\dfrac{15}{7}\)
        \item \(\dfrac{72}{21}\div\dfrac{56}{14}=\underline{\hspace{3cm}}\)\dfrac{6}{7}\)
        \item \(4\dfrac{3}{9}-7\dfrac{7}{12}=\underline{\hspace{3cm}}\)11\dfrac{11}{12}\)
    \end{enumerate}
\end{multicols}

\textbf{p4}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(4\dfrac{4}{6}+6\dfrac{8}{9}=\underline{\hspace{3cm}}\)11\dfrac{5}{9}\)
        \item \(3\dfrac{5}{10}+9\dfrac{1}{5}=\underline{\hspace{3cm}}\)12\dfrac{7}{10}\)
        \item \(4\dfrac{2}{10}+4\dfrac{4}{8}=\underline{\hspace{3cm}}\)8\dfrac{7}{10}\)
        \item \(5\dfrac{3}{12}-9\dfrac{9}{10}=\underline{\hspace{3cm}}\)15\dfrac{3}{20}\)
        \item \(8\dfrac{6}{10}-6\dfrac{3}{4}=\underline{\hspace{3cm}}\)15\dfrac{7}{20}\)
        \item \(2\dfrac{1}{4}+8\dfrac{3}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{2}\)
        \item \(6\dfrac{8}{9}+8\dfrac{10}{12}=\underline{\hspace{3cm}}\)15\dfrac{13}{18}\)
        \item \(\dfrac{27}{24}\times\dfrac{88}{66}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(5\dfrac{4}{12}-9\dfrac{2}{4}=\underline{\hspace{3cm}}\)14\dfrac{5}{6}\)
        \item \(7\dfrac{4}{6}-6\dfrac{1}{4}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(4\dfrac{10}{12}+5\dfrac{5}{6}=\underline{\hspace{3cm}}\)10\dfrac{2}{3}\)
        \item \(\dfrac{98}{78}\div\dfrac{21}{18}=\underline{\hspace{3cm}}\)\dfrac{14}{13}\)
        \item \(2\dfrac{7}{9}-9\dfrac{5}{6}=\underline{\hspace{3cm}}\)12\dfrac{11}{18}\)
        \item \(2\dfrac{4}{8}-8\dfrac{9}{12}=\underline{\hspace{3cm}}\)11\dfrac{1}{4}\)
        \item \(9\dfrac{3}{9}+9\dfrac{3}{4}=\underline{\hspace{3cm}}\)19\dfrac{1}{12}\)
        \item \(9\dfrac{6}{7}+6\dfrac{6}{12}=\underline{\hspace{3cm}}\)16\dfrac{5}{14}\)
        \item \(7\dfrac{3}{6}+6\dfrac{1}{4}=\underline{\hspace{3cm}}\)13\dfrac{3}{4}\)
        \item \(4\dfrac{2}{8}-6\dfrac{5}{12}=\underline{\hspace{3cm}}\)10\dfrac{2}{3}\)
        \item \(\dfrac{80}{16}\div\dfrac{25}{60}=\underline{\hspace{3cm}}\)\dfrac{12}{1}\)
        \item \(\dfrac{51}{9}\div\dfrac{74}{37}=\underline{\hspace{3cm}}\)\dfrac{17}{6}\)
    \end{enumerate}
\end{multicols}

\textbf{p5}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(6\dfrac{6}{9}-2\dfrac{3}{4}=\underline{\hspace{3cm}}\)9\dfrac{5}{12}\)
        \item \(\dfrac{22}{9}\times\dfrac{35}{77}=\underline{\hspace{3cm}}\)\dfrac{10}{9}\)
        \item \(\dfrac{16}{12}\div\dfrac{8}{10}=\underline{\hspace{3cm}}\)\dfrac{5}{3}\)
        \item \(3\dfrac{1}{6}+3\dfrac{1}{10}=\underline{\hspace{3cm}}\)6\dfrac{4}{15}\)
        \item \(\dfrac{60}{35}\div\dfrac{24}{56}=\underline{\hspace{3cm}}\)\dfrac{4}{1}\)
        \item \(5\dfrac{8}{9}+4\dfrac{2}{4}=\underline{\hspace{3cm}}\)10\dfrac{7}{18}\)
        \item \(2\dfrac{4}{6}-6\dfrac{4}{8}=\underline{\hspace{3cm}}\)9\dfrac{1}{6}\)
        \item \(4\dfrac{3}{10}-8\dfrac{3}{4}=\underline{\hspace{3cm}}\)13\dfrac{1}{20}\)
        \item \(3\dfrac{5}{10}-5\dfrac{1}{6}=\underline{\hspace{3cm}}\)8\dfrac{2}{3}\)
        \item \(9\dfrac{1}{2}+7\dfrac{7}{9}=\underline{\hspace{3cm}}\)17\dfrac{5}{18}\)
        \item \(3\dfrac{2}{10}+7\dfrac{4}{8}=\underline{\hspace{3cm}}\)10\dfrac{7}{10}\)
        \item \(5\dfrac{6}{12}-6\dfrac{2}{4}=\underline{\hspace{3cm}}\)-12\)
        \item \(1\dfrac{20}{32}\times2\dfrac{10}{39}=\underline{\hspace{3cm}}\)\dfrac{11}{3}\)
        \item \(\dfrac{77}{99}\div\dfrac{12}{18}=\underline{\hspace{3cm}}\)\dfrac{7}{6}\)
        \item \(\dfrac{12}{21}\div\dfrac{32}{76}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(2\dfrac{2}{3}+3\dfrac{8}{10}=\underline{\hspace{3cm}}\)6\dfrac{7}{15}\)
        \item \(\dfrac{52}{90}\times\dfrac{80}{64}=\underline{\hspace{3cm}}\)\dfrac{13}{18}\)
        \item \(3\dfrac{1}{10}-6\dfrac{6}{12}=\underline{\hspace{3cm}}\)9\dfrac{3}{5}\)
        \item \(3\dfrac{4}{8}+2\dfrac{10}{12}=\underline{\hspace{3cm}}\)6\dfrac{1}{3}\)
        \item \(7\dfrac{3}{4}-5\dfrac{4}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{12}\)
    \end{enumerate}
\end{multicols}

\newpage

\textbf{p6}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(5\dfrac{3}{5}+3\dfrac{9}{12}=\underline{\hspace{3cm}}\)9\dfrac{7}{20}\)
        \item \(\dfrac{33}{44}\div\dfrac{72}{66}=\underline{\hspace{3cm}}\)\dfrac{11}{16}\)
        \item \(9\dfrac{4}{10}-9\dfrac{3}{12}=\underline{\hspace{3cm}}\)18\dfrac{13}{20}\)
        \item \(\dfrac{2}{4}\div\dfrac{21}{6}=\underline{\hspace{3cm}}\)\dfrac{1}{7}\)
        \item \(7\dfrac{3}{5}-5\dfrac{1}{2}=\underline{\hspace{3cm}}\)13\dfrac{1}{10}\)
        \item \(5\dfrac{1}{12}+6\dfrac{6}{8}=\underline{\hspace{3cm}}\)11\dfrac{5}{6}\)
        \item \(\dfrac{90}{45}\div\dfrac{21}{49}=\underline{\hspace{3cm}}\)\dfrac{14}{3}\)
        \item \(3\dfrac{5}{15}\times1\dfrac{8}{10}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(\dfrac{10}{33}\times\dfrac{99}{9}=\underline{\hspace{3cm}}\)\dfrac{10}{3}\)
        \item \(3\dfrac{5}{12}-3\dfrac{1}{6}=\underline{\hspace{3cm}}\)6\dfrac{7}{12}\)
        \item \(\dfrac{60}{50}\div\dfrac{30}{15}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(4\dfrac{2}{8}-6\dfrac{9}{10}=\underline{\hspace{3cm}}\)11\dfrac{3}{20}\)
        \item \(5\dfrac{2}{8}+7\dfrac{11}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{6}\)
        \item \(8\dfrac{6}{12}-8\dfrac{5}{9}=\underline{\hspace{3cm}}\)17\dfrac{1}{18}\)
        \item \(\dfrac{34}{2}\div\dfrac{50}{5}=\underline{\hspace{3cm}}\)\dfrac{17}{10}\)
        \item \(5\dfrac{1}{10}+2\dfrac{1}{2}=\underline{\hspace{3cm}}\)7\dfrac{3}{5}\)
        \item \(5\dfrac{3}{4}+5\dfrac{2}{5}=\underline{\hspace{3cm}}\)11\dfrac{3}{20}\)
        \item \(\dfrac{13}{26}\div\dfrac{12}{14}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(3\dfrac{8}{10}-6\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{20}\)
        \item \(\dfrac{57}{96}\times\dfrac{16}{3}=\underline{\hspace{3cm}}\)\dfrac{19}{6}\)
    \end{enumerate}
\end{multicols}

\textbf{p7}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(4\dfrac{5}{12}+4\dfrac{5}{10}=\underline{\hspace{3cm}}\)8\dfrac{11}{12}\)
        \item \(\dfrac{92}{23}\div\dfrac{7}{14}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(4\dfrac{6}{10}+3\dfrac{1}{3}=\underline{\hspace{3cm}}\)7\dfrac{14}{15}\)
        \item \(\dfrac{9}{15}\div\dfrac{37}{74}=\underline{\hspace{3cm}}\)\dfrac{6}{5}\)
        \item \(4\dfrac{4}{9}+7\dfrac{4}{6}=\underline{\hspace{3cm}}\)12\dfrac{1}{9}\)
        \item \(8\dfrac{3}{5}-5\dfrac{1}{2}=\underline{\hspace{3cm}}\)14\dfrac{1}{10}\)
        \item \(\dfrac{20}{22}\div\dfrac{38}{57}=\underline{\hspace{3cm}}\)\dfrac{15}{11}\)
        \item \(6\dfrac{2}{9}+9\dfrac{10}{12}=\underline{\hspace{3cm}}\)16\dfrac{1}{18}\)
        \item \(2\dfrac{8}{10}+7\dfrac{8}{12}=\underline{\hspace{3cm}}\)10\dfrac{7}{15}\)
        \item \(5\dfrac{8}{10}+6\dfrac{2}{4}=\underline{\hspace{3cm}}\)12\dfrac{3}{10}\)
        \item \(4\dfrac{7}{12}+2\dfrac{3}{9}=\underline{\hspace{3cm}}\)6\dfrac{11}{12}\)
        \item \(8\dfrac{1}{3}-6\dfrac{9}{12}=\underline{\hspace{3cm}}\)15\dfrac{1}{12}\)
        \item \(7\dfrac{2}{8}+6\dfrac{6}{9}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(\dfrac{12}{96}\div\dfrac{9}{84}=\underline{\hspace{3cm}}\)\dfrac{7}{6}\)
        \item \(2\dfrac{3}{6}+2\dfrac{6}{8}=\underline{\hspace{3cm}}\)5\dfrac{1}{4}\)
        \item \(7\dfrac{3}{10}-9\dfrac{1}{5}=\underline{\hspace{3cm}}\)16\dfrac{1}{2}\)
        \item \(\dfrac{24}{90}\div\dfrac{48}{75}=\underline{\hspace{3cm}}\)\dfrac{5}{12}\)
        \item \(3\dfrac{1}{2}+2\dfrac{7}{9}=\underline{\hspace{3cm}}\)6\dfrac{5}{18}\)
        \item \(\dfrac{12}{14}\times\dfrac{11}{22}=\underline{\hspace{3cm}}\)\dfrac{3}{7}\)
        \item \(3\dfrac{7}{12}-2\dfrac{1}{3}=\underline{\hspace{3cm}}\)5\dfrac{11}{12}\)
    \end{enumerate}
\end{multicols}

\textbf{p8}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(2\dfrac{3}{4}\times\dfrac{45}{55}=\underline{\hspace{3cm}}\)\dfrac{9}{4}\)
        \item \(\dfrac{21}{49}\times\dfrac{84}{57}=\underline{\hspace{3cm}}\)\dfrac{12}{19}\)
        \item \(\dfrac{38}{19}\div\dfrac{8}{24}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(\dfrac{33}{45}\div\dfrac{33}{63}=\underline{\hspace{3cm}}\)\dfrac{7}{5}\)
        \item \(9\dfrac{1}{3}+6\dfrac{4}{9}=\underline{\hspace{3cm}}\)15\dfrac{7}{9}\)
        \item \(5\dfrac{7}{12}+2\dfrac{5}{10}=\underline{\hspace{3cm}}\)8\dfrac{1}{12}\)
        \item \(\dfrac{4}{6}\div\dfrac{33}{63}=\underline{\hspace{3cm}}\)\dfrac{14}{11}\)
        \item \(9\dfrac{1}{2}+5\dfrac{6}{8}=\underline{\hspace{3cm}}\)15\dfrac{1}{4}\)
        \item \(\dfrac{50}{85}\times1\dfrac{7}{14}=\underline{\hspace{3cm}}\)\dfrac{15}{17}\)
        \item \(\dfrac{63}{98}\times3\dfrac{17}{27}=\underline{\hspace{3cm}}\)\dfrac{7}{3}\)
        \item \(6\dfrac{5}{6}+7\dfrac{4}{12}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
        \item \(\dfrac{11}{62}\times1\dfrac{29}{33}=\underline{\hspace{3cm}}\)\dfrac{1}{3}\)
        \item \(\dfrac{18}{12}\times\dfrac{24}{99}=\underline{\hspace{3cm}}\)\dfrac{4}{11}\)
        \item \(\dfrac{55}{35}\times\dfrac{35}{99}=\underline{\hspace{3cm}}\)\dfrac{5}{9}\)
        \item \(6\dfrac{2}{9}+4\dfrac{5}{6}=\underline{\hspace{3cm}}\)11\dfrac{1}{18}\)
        \item \(9\dfrac{1}{5}+6\dfrac{6}{12}=\underline{\hspace{3cm}}\)15\dfrac{7}{10}\)
        \item \(5\dfrac{2}{12}+8\dfrac{5}{6}=\underline{\hspace{3cm}}\)-14\)
        \item \(\dfrac{52}{40}\div\dfrac{9}{30}=\underline{\hspace{3cm}}\)\dfrac{13}{3}\)
        \item \(6\dfrac{6}{10}+7\dfrac{1}{4}=\underline{\hspace{3cm}}\)13\dfrac{17}{20}\)
        \item \(9\dfrac{5}{10}-7\dfrac{2}{6}=\underline{\hspace{3cm}}\)16\dfrac{5}{6}\)
    \end{enumerate}
\end{multicols}

\textbf{p9}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{46}{2}\times\dfrac{6}{46}=\underline{\hspace{3cm}}\)\dfrac{3}{1}\)
        \item \(9\dfrac{3}{5}-8\dfrac{2}{10}=\underline{\hspace{3cm}}\)17\dfrac{4}{5}\)
        \item \(\dfrac{84}{17}\times\dfrac{17}{35}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(\dfrac{30}{35}\div\dfrac{50}{35}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(\dfrac{45}{33}\div\dfrac{30}{14}=\underline{\hspace{3cm}}\)\dfrac{7}{11}\)
        \item \(\dfrac{36}{68}\div\dfrac{81}{45}=\underline{\hspace{3cm}}\)\dfrac{5}{17}\)
        \item \(\dfrac{26}{13}\div\dfrac{12}{84}=\underline{\hspace{3cm}}\)\dfrac{14}{1}\)
        \item \(\dfrac{20}{24}\div\dfrac{30}{4}=\underline{\hspace{3cm}}\)\dfrac{1}{9}\)
        \item \(2\dfrac{2}{6}-4\dfrac{4}{10}=\underline{\hspace{3cm}}\)6\dfrac{11}{15}\)
        \item \(\dfrac{54}{15}\times\dfrac{80}{16}=\underline{\hspace{3cm}}\)\dfrac{18}{1}\)
        \item \(\dfrac{80}{45}\div\dfrac{24}{36}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(7\dfrac{1}{2}-5\dfrac{4}{7}=\underline{\hspace{3cm}}\)13\dfrac{1}{14}\)
        \item \(6\dfrac{3}{4}+9\dfrac{2}{5}=\underline{\hspace{3cm}}\)16\dfrac{3}{20}\)
        \item \(6\dfrac{4}{8}-4\dfrac{3}{9}=\underline{\hspace{3cm}}\)10\dfrac{5}{6}\)
        \item \(7\dfrac{8}{12}+3\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{11}{12}\)
        \item \(6\dfrac{2}{4}+5\dfrac{3}{10}=\underline{\hspace{3cm}}\)11\dfrac{4}{5}\)
        \item \(2\dfrac{22}{28}\times\dfrac{19}{39}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(\dfrac{90}{45}\times\dfrac{56}{42}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(4\dfrac{4}{6}+8\dfrac{10}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{2}\)
        \item \(9\dfrac{2}{3}-4\dfrac{3}{9}=\underline{\hspace{3cm}}\)-14\)
    \end{enumerate}
\end{multicols}

\textbf{p10}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(2\dfrac{2}{5}+4\dfrac{3}{12}=\underline{\hspace{3cm}}\)6\dfrac{13}{20}\)
        \item \(\dfrac{5}{17}\times\dfrac{34}{55}=\underline{\hspace{3cm}}\)\dfrac{2}{11}\)
        \item \(3\dfrac{6}{9}+8\dfrac{2}{3}=\underline{\hspace{3cm}}\)12\dfrac{1}{3}\)
        \item \(9\dfrac{1}{2}+2\dfrac{10}{12}=\underline{\hspace{3cm}}\)12\dfrac{1}{3}\)
        \item \(2\dfrac{8}{10}-7\dfrac{2}{5}=\underline{\hspace{3cm}}\)10\dfrac{1}{5}\)
        \item \(5\dfrac{1}{2}-7\dfrac{7}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{12}\)
        \item \(2\dfrac{4}{16}\times1\dfrac{6}{90}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(5\dfrac{1}{3}-5\dfrac{4}{12}=\underline{\hspace{3cm}}\)10\dfrac{2}{3}\)
        \item \(6\dfrac{6}{8}+2\dfrac{1}{5}=\underline{\hspace{3cm}}\)8\dfrac{19}{20}\)
        \item \(\dfrac{26}{96}\times\dfrac{96}{32}=\underline{\hspace{3cm}}\)\dfrac{13}{16}\)
        \item \(2\dfrac{1}{5}+6\dfrac{8}{12}=\underline{\hspace{3cm}}\)8\dfrac{13}{15}\)
        \item \(\dfrac{65}{25}\div\dfrac{26}{10}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{52}{32}\div\dfrac{49}{56}=\underline{\hspace{3cm}}\)\dfrac{13}{7}\)
        \item \(\dfrac{24}{2}\div\dfrac{84}{7}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{36}{84}\div\dfrac{10}{42}=\underline{\hspace{3cm}}\)\dfrac{9}{5}\)
        \item \(3\dfrac{2}{4}-8\dfrac{1}{5}=\underline{\hspace{3cm}}\)11\dfrac{7}{10}\)
        \item \(9\dfrac{1}{6}-6\dfrac{2}{3}=\underline{\hspace{3cm}}\)15\dfrac{5}{6}\)
        \item \(7\dfrac{1}{4}+8\dfrac{1}{3}=\underline{\hspace{3cm}}\)15\dfrac{7}{12}\)
        \item \(6\dfrac{3}{4}-6\dfrac{8}{12}=\underline{\hspace{3cm}}\)13\dfrac{5}{12}\)
        \item \(\dfrac{38}{54}\div\dfrac{30}{81}=\underline{\hspace{3cm}}\)\dfrac{19}{10}\)
    \end{enumerate}
\end{multicols}

\newpage

\textbf{p11}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(2\dfrac{2}{3}+6\dfrac{4}{10}=\underline{\hspace{3cm}}\)9\dfrac{1}{15}\)
        \item \(8\dfrac{2}{8}+5\dfrac{5}{6}=\underline{\hspace{3cm}}\)14\dfrac{1}{12}\)
        \item \(\dfrac{25}{70}\div\dfrac{15}{6}=\underline{\hspace{3cm}}\)\dfrac{1}{7}\)
        \item \(9\dfrac{2}{9}+2\dfrac{1}{2}=\underline{\hspace{3cm}}\)11\dfrac{13}{18}\)
        \item \(1\dfrac{2}{4}\times\dfrac{24}{76}=\underline{\hspace{3cm}}\)\dfrac{9}{19}\)
        \item \(5\dfrac{4}{5}+2\dfrac{2}{8}=\underline{\hspace{3cm}}\)8\dfrac{1}{20}\)
        \item \(3\dfrac{4}{5}+8\dfrac{7}{10}=\underline{\hspace{3cm}}\)12\dfrac{1}{2}\)
        \item \(\dfrac{10}{18}\div\dfrac{40}{8}=\underline{\hspace{3cm}}\)\dfrac{1}{9}\)
        \item \(\dfrac{93}{62}\div\dfrac{99}{30}=\underline{\hspace{3cm}}\)\dfrac{5}{11}\)
        \item \(4\dfrac{6}{8}-6\dfrac{3}{5}=\underline{\hspace{3cm}}\)11\dfrac{7}{20}\)
        \item \(8\dfrac{7}{9}+3\dfrac{4}{8}=\underline{\hspace{3cm}}\)12\dfrac{5}{18}\)
        \item \(8\dfrac{6}{8}-8\dfrac{9}{12}=\underline{\hspace{3cm}}\)17\dfrac{1}{2}\)
        \item \(6\dfrac{2}{12}+5\dfrac{4}{9}=\underline{\hspace{3cm}}\)11\dfrac{11}{18}\)
        \item \(5\dfrac{1}{10}+6\dfrac{1}{2}=\underline{\hspace{3cm}}\)11\dfrac{3}{5}\)
        \item \(\dfrac{65}{80}\times\dfrac{76}{26}=\underline{\hspace{3cm}}\)\dfrac{19}{8}\)
        \item \(3\dfrac{3}{5}-2\dfrac{3}{10}=\underline{\hspace{3cm}}\)5\dfrac{9}{10}\)
        \item \(\dfrac{14}{36}\times\dfrac{15}{10}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(6\dfrac{2}{10}+4\dfrac{6}{12}=\underline{\hspace{3cm}}\)10\dfrac{7}{10}\)
        \item \(\dfrac{12}{72}\div\dfrac{15}{60}=\underline{\hspace{3cm}}\)\dfrac{2}{3}\)
        \item \(5\dfrac{3}{9}+8\dfrac{1}{12}=\underline{\hspace{3cm}}\)13\dfrac{5}{12}\)
    \end{enumerate}
\end{multicols}

\textbf{p12}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{87}{29}\div\dfrac{10}{8}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(1\dfrac{3}{44}\times\dfrac{8}{94}=\underline{\hspace{3cm}}\)\dfrac{1}{11}\)
        \item \(2\dfrac{2}{5}+5\dfrac{4}{6}=\underline{\hspace{3cm}}\)8\dfrac{1}{15}\)
        \item \(7\dfrac{4}{9}-4\dfrac{1}{6}=\underline{\hspace{3cm}}\)11\dfrac{11}{18}\)
        \item \(\dfrac{70}{45}\div\dfrac{34}{17}=\underline{\hspace{3cm}}\)\dfrac{7}{9}\)
        \item \(3\dfrac{3}{12}\times\dfrac{50}{75}=\underline{\hspace{3cm}}\)\dfrac{13}{6}\)
        \item \(\dfrac{34}{2}\div\dfrac{56}{8}=\underline{\hspace{3cm}}\)\dfrac{17}{7}\)
        \item \(6\dfrac{4}{10}+4\dfrac{2}{5}=\underline{\hspace{3cm}}\)10\dfrac{4}{5}\)
        \item \(\dfrac{10}{53}\times1\dfrac{18}{35}=\underline{\hspace{3cm}}\)\dfrac{2}{7}\)
        \item \(6\dfrac{8}{9}-8\dfrac{4}{6}=\underline{\hspace{3cm}}\)15\dfrac{5}{9}\)
        \item \(\dfrac{10}{28}\div\dfrac{90}{28}=\underline{\hspace{3cm}}\)\dfrac{1}{9}\)
        \item \(\dfrac{60}{84}\div\dfrac{25}{85}=\underline{\hspace{3cm}}\)\dfrac{17}{7}\)
        \item \(1\dfrac{12}{40}\times1\dfrac{9}{36}=\underline{\hspace{3cm}}\)\dfrac{13}{8}\)
        \item \(3\dfrac{1}{10}+6\dfrac{1}{6}=\underline{\hspace{3cm}}\)9\dfrac{4}{15}\)
        \item \(2\dfrac{7}{8}-7\dfrac{2}{4}=\underline{\hspace{3cm}}\)10\dfrac{3}{8}\)
        \item \(\dfrac{88}{12}\div\dfrac{88}{66}=\underline{\hspace{3cm}}\)\dfrac{11}{2}\)
        \item \(1\dfrac{20}{30}\times2\dfrac{21}{30}=\underline{\hspace{3cm}}\)\dfrac{9}{2}\)
        \item \(2\dfrac{4}{9}-8\dfrac{1}{2}=\underline{\hspace{3cm}}\)10\dfrac{17}{18}\)
        \item \(\dfrac{88}{30}\times\dfrac{2}{88}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
        \item \(\dfrac{2}{28}\div\dfrac{9}{42}=\underline{\hspace{3cm}}\)\dfrac{1}{3}\)
    \end{enumerate}
\end{multicols}

\textbf{p13}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(3\dfrac{1}{2}-2\dfrac{5}{6}=\underline{\hspace{3cm}}\)6\dfrac{1}{3}\)
        \item \(6\dfrac{5}{10}-6\dfrac{4}{5}=\underline{\hspace{3cm}}\)13\dfrac{3}{10}\)
        \item \(\dfrac{77}{42}\div\dfrac{6}{2}=\underline{\hspace{3cm}}\)\dfrac{11}{18}\)
        \item \(\dfrac{29}{58}\div\dfrac{57}{19}=\underline{\hspace{3cm}}\)\dfrac{1}{6}\)
        \item \(8\dfrac{1}{3}-7\dfrac{2}{12}=\underline{\hspace{3cm}}\)15\dfrac{1}{2}\)
        \item \(9\dfrac{10}{12}-7\dfrac{4}{6}=\underline{\hspace{3cm}}\)17\dfrac{1}{2}\)
        \item \(\dfrac{60}{63}\times\dfrac{84}{60}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{6}{24}\div\dfrac{2}{3}=\underline{\hspace{3cm}}\)\dfrac{3}{8}\)
        \item \(\dfrac{12}{48}\times\dfrac{54}{24}=\underline{\hspace{3cm}}\)\dfrac{9}{16}\)
        \item \(\dfrac{2}{4}\div\dfrac{60}{75}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(9\dfrac{5}{6}-2\dfrac{1}{9}=\underline{\hspace{3cm}}\)11\dfrac{17}{18}\)
        \item \(\dfrac{27}{30}\div\dfrac{54}{78}=\underline{\hspace{3cm}}\)\dfrac{13}{10}\)
        \item \(1\dfrac{30}{66}\times1\dfrac{12}{54}=\underline{\hspace{3cm}}\)\dfrac{16}{9}\)
        \item \(3\dfrac{5}{10}+9\dfrac{5}{12}=\underline{\hspace{3cm}}\)12\dfrac{11}{12}\)
        \item \(4\dfrac{4}{5}+8\dfrac{3}{12}=\underline{\hspace{3cm}}\)13\dfrac{1}{20}\)
        \item \(9\dfrac{1}{5}+9\dfrac{3}{12}=\underline{\hspace{3cm}}\)18\dfrac{9}{20}\)
        \item \(\dfrac{25}{80}\times\dfrac{9}{15}=\underline{\hspace{3cm}}\)\dfrac{3}{16}\)
        \item \(\dfrac{12}{60}\div\dfrac{19}{95}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{36}{54}\times\dfrac{6}{68}=\underline{\hspace{3cm}}\)\dfrac{1}{17}\)
        \item \(\dfrac{2}{16}\div\dfrac{38}{32}=\underline{\hspace{3cm}}\)\dfrac{2}{19}\)
    \end{enumerate}
\end{multicols}

\textbf{p14}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(2\dfrac{3}{9}-5\dfrac{3}{6}=\underline{\hspace{3cm}}\)7\dfrac{5}{6}\)
        \item \(\dfrac{16}{25}\times\dfrac{50}{34}=\underline{\hspace{3cm}}\)\dfrac{16}{17}\)
        \item \(5\dfrac{2}{12}-9\dfrac{3}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{2}\)
        \item \(6\dfrac{4}{6}-7\dfrac{6}{8}=\underline{\hspace{3cm}}\)14\dfrac{5}{12}\)
        \item \(2\dfrac{3}{5}+6\dfrac{9}{12}=\underline{\hspace{3cm}}\)9\dfrac{7}{20}\)
        \item \(\dfrac{38}{40}\div\dfrac{72}{80}=\underline{\hspace{3cm}}\)\dfrac{19}{18}\)
        \item \(3\dfrac{2}{4}-8\dfrac{4}{8}=\underline{\hspace{3cm}}\)-12\)
        \item \(\dfrac{38}{12}\div\dfrac{76}{24}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(5\dfrac{3}{5}+9\dfrac{3}{10}=\underline{\hspace{3cm}}\)14\dfrac{9}{10}\)
        \item \(9\dfrac{8}{12}-9\dfrac{6}{10}=\underline{\hspace{3cm}}\)19\dfrac{4}{15}\)
        \item \(1\dfrac{10}{54}\times\dfrac{72}{80}=\underline{\hspace{3cm}}\)\dfrac{16}{15}\)
        \item \(\dfrac{46}{45}\div\dfrac{69}{90}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{8}{98}\div\dfrac{72}{63}=\underline{\hspace{3cm}}\)\dfrac{1}{14}\)
        \item \(\dfrac{30}{58}\times\dfrac{58}{5}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(\dfrac{14}{4}\times\dfrac{32}{28}=\underline{\hspace{3cm}}\)\dfrac{4}{1}\)
        \item \(\dfrac{50}{60}\times\dfrac{76}{10}=\underline{\hspace{3cm}}\)\dfrac{19}{3}\)
        \item \(\dfrac{33}{75}\div\dfrac{66}{75}=\underline{\hspace{3cm}}\)\dfrac{1}{2}\)
        \item \(\dfrac{95}{20}\div\dfrac{25}{10}=\underline{\hspace{3cm}}\)\dfrac{19}{10}\)
        \item \(1\dfrac{13}{65}\times\dfrac{20}{24}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(5\dfrac{1}{9}-4\dfrac{8}{12}=\underline{\hspace{3cm}}\)9\dfrac{7}{9}\)
    \end{enumerate}
\end{multicols}

\textbf{p15}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{48}{86}\times1\dfrac{4}{39}=\underline{\hspace{3cm}}\)\dfrac{8}{13}\)
        \item \(\dfrac{48}{10}\div\dfrac{28}{7}=\underline{\hspace{3cm}}\)\dfrac{6}{5}\)
        \item \(6\dfrac{6}{8}-6\dfrac{3}{4}=\underline{\hspace{3cm}}\)13\dfrac{1}{2}\)
        \item \(7\dfrac{1}{6}+3\dfrac{7}{12}=\underline{\hspace{3cm}}\)10\dfrac{3}{4}\)
        \item \(8\dfrac{8}{12}+4\dfrac{2}{3}=\underline{\hspace{3cm}}\)13\dfrac{1}{3}\)
        \item \(6\dfrac{1}{4}+7\dfrac{2}{6}=\underline{\hspace{3cm}}\)13\dfrac{7}{12}\)
        \item \(\dfrac{42}{12}\div\dfrac{98}{70}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(\dfrac{54}{27}\div\dfrac{20}{12}=\underline{\hspace{3cm}}\)\dfrac{6}{5}\)
        \item \(8\dfrac{2}{4}+6\dfrac{2}{6}=\underline{\hspace{3cm}}\)14\dfrac{5}{6}\)
        \item \(8\dfrac{4}{5}+4\dfrac{5}{10}=\underline{\hspace{3cm}}\)13\dfrac{3}{10}\)
        \item \(\dfrac{95}{76}\div\dfrac{55}{66}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(\dfrac{24}{78}\times4\dfrac{7}{21}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{54}{72}\div\dfrac{62}{93}=\underline{\hspace{3cm}}\)\dfrac{9}{8}\)
        \item \(7\dfrac{2}{8}+4\dfrac{3}{6}=\underline{\hspace{3cm}}\)11\dfrac{3}{4}\)
        \item \(9\dfrac{5}{8}+3\dfrac{1}{2}=\underline{\hspace{3cm}}\)13\dfrac{1}{8}\)
        \item \(4\dfrac{4}{6}-6\dfrac{4}{8}=\underline{\hspace{3cm}}\)11\dfrac{1}{6}\)
        \item \(2\dfrac{6}{8}+6\dfrac{1}{10}=\underline{\hspace{3cm}}\)8\dfrac{17}{20}\)
        \item \(1\dfrac{16}{40}\times\dfrac{15}{28}=\underline{\hspace{3cm}}\)\dfrac{3}{4}\)
        \item \(\dfrac{4}{3}\div\dfrac{36}{72}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(8\dfrac{9}{12}-9\dfrac{6}{8}=\underline{\hspace{3cm}}\)18\dfrac{1}{2}\)
    \end{enumerate}
\end{multicols}

\newpage

\textbf{p16}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(2\dfrac{2}{12}-3\dfrac{5}{9}=\underline{\hspace{3cm}}\)5\dfrac{13}{18}\)
        \item \(\dfrac{99}{11}\div\dfrac{10}{5}=\underline{\hspace{3cm}}\)\dfrac{9}{2}\)
        \item \(2\dfrac{3}{10}-6\dfrac{2}{8}=\underline{\hspace{3cm}}\)8\dfrac{11}{20}\)
        \item \(2\dfrac{5}{10}+5\dfrac{3}{4}=\underline{\hspace{3cm}}\)8\dfrac{1}{4}\)
        \item \(6\dfrac{4}{10}+6\dfrac{2}{3}=\underline{\hspace{3cm}}\)13\dfrac{1}{15}\)
        \item \(\dfrac{85}{51}\div\dfrac{9}{54}=\underline{\hspace{3cm}}\)\dfrac{10}{1}\)
        \item \(6\dfrac{1}{2}-6\dfrac{9}{10}=\underline{\hspace{3cm}}\)13\dfrac{2}{5}\)
        \item \(8\dfrac{1}{10}+5\dfrac{3}{5}=\underline{\hspace{3cm}}\)13\dfrac{7}{10}\)
        \item \(\dfrac{16}{68}\div\dfrac{19}{38}=\underline{\hspace{3cm}}\)\dfrac{8}{17}\)
        \item \(2\dfrac{14}{35}\times\dfrac{4}{6}=\underline{\hspace{3cm}}\)\dfrac{8}{5}\)
        \item \(\dfrac{70}{60}\times\dfrac{15}{5}=\underline{\hspace{3cm}}\)\dfrac{7}{2}\)
        \item \(\dfrac{90}{98}\div\dfrac{12}{98}=\underline{\hspace{3cm}}\)\dfrac{15}{2}\)
        \item \(9\dfrac{5}{9}+6\dfrac{5}{6}=\underline{\hspace{3cm}}\)16\dfrac{7}{18}\)
        \item \(\dfrac{78}{57}\div\dfrac{16}{38}=\underline{\hspace{3cm}}\)\dfrac{13}{4}\)
        \item \(\dfrac{21}{56}\div\dfrac{5}{80}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(5\dfrac{5}{10}-4\dfrac{2}{3}=\underline{\hspace{3cm}}\)10\dfrac{1}{6}\)
        \item \(1\dfrac{28}{42}\times1\dfrac{22}{50}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(\dfrac{60}{32}\times\dfrac{17}{51}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(7\dfrac{2}{4}+6\dfrac{2}{6}=\underline{\hspace{3cm}}\)13\dfrac{5}{6}\)
        \item \(2\dfrac{2}{4}+3\dfrac{2}{3}=\underline{\hspace{3cm}}\)6\dfrac{1}{6}\)
    \end{enumerate}
\end{multicols}

\textbf{p17}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(1\dfrac{30}{39}\times\dfrac{12}{69}=\underline{\hspace{3cm}}\)\dfrac{4}{13}\)
        \item \(\dfrac{30}{72}\times5\dfrac{2}{10}=\underline{\hspace{3cm}}\)\dfrac{13}{6}\)
        \item \(\dfrac{28}{52}\div\dfrac{77}{11}=\underline{\hspace{3cm}}\)\dfrac{1}{13}\)
        \item \(1\dfrac{24}{54}\times\dfrac{25}{50}=\underline{\hspace{3cm}}\)\dfrac{13}{18}\)
        \item \(\dfrac{42}{63}\div\dfrac{3}{36}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(\dfrac{80}{56}\times\dfrac{11}{44}=\underline{\hspace{3cm}}\)\dfrac{5}{14}\)
        \item \(\dfrac{63}{66}\times\dfrac{42}{49}=\underline{\hspace{3cm}}\)\dfrac{9}{11}\)
        \item \(\dfrac{14}{21}\div\dfrac{21}{42}=\underline{\hspace{3cm}}\)\dfrac{4}{3}\)
        \item \(\dfrac{48}{88}\times\dfrac{85}{51}=\underline{\hspace{3cm}}\)\dfrac{10}{11}\)
        \item \(\dfrac{52}{72}\div\dfrac{26}{22}=\underline{\hspace{3cm}}\)\dfrac{11}{18}\)
        \item \(\dfrac{14}{63}\div\dfrac{18}{81}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(\dfrac{72}{12}\div\dfrac{88}{4}=\underline{\hspace{3cm}}\)\dfrac{3}{11}\)
        \item \(3\dfrac{18}{24}\times\dfrac{8}{30}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(3\dfrac{5}{10}-8\dfrac{1}{9}=\underline{\hspace{3cm}}\)11\dfrac{11}{18}\)
        \item \(\dfrac{18}{39}\div\dfrac{76}{78}=\underline{\hspace{3cm}}\)\dfrac{9}{19}\)
        \item \(5\dfrac{2}{6}+3\dfrac{2}{4}=\underline{\hspace{3cm}}\)8\dfrac{5}{6}\)
        \item \(\dfrac{3}{54}\div\dfrac{6}{63}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(9\dfrac{6}{12}-3\dfrac{5}{10}=\underline{\hspace{3cm}}\)-13\)
        \item \(2\dfrac{1}{28}\times1\dfrac{6}{18}=\underline{\hspace{3cm}}\)\dfrac{19}{7}\)
        \item \(4\dfrac{2}{7}-4\dfrac{3}{6}=\underline{\hspace{3cm}}\)8\dfrac{11}{14}\)
    \end{enumerate}
\end{multicols}

\textbf{p18}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{70}{35}\div\dfrac{24}{12}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(1\dfrac{15}{20}\times1\dfrac{22}{42}=\underline{\hspace{3cm}}\)\dfrac{8}{3}\)
        \item \(\dfrac{10}{48}\times\dfrac{48}{22}=\underline{\hspace{3cm}}\)\dfrac{5}{11}\)
        \item \(\dfrac{6}{58}\times1\dfrac{13}{45}=\underline{\hspace{3cm}}\)\dfrac{2}{15}\)
        \item \(\dfrac{75}{54}\div\dfrac{60}{18}=\underline{\hspace{3cm}}\)\dfrac{5}{12}\)
        \item \(6\dfrac{6}{12}-5\dfrac{6}{10}=\underline{\hspace{3cm}}\)12\dfrac{1}{10}\)
        \item \(\dfrac{75}{11}\times\dfrac{22}{70}=\underline{\hspace{3cm}}\)\dfrac{15}{7}\)
        \item \(4\dfrac{1}{9}+5\dfrac{4}{12}=\underline{\hspace{3cm}}\)9\dfrac{4}{9}\)
        \item \(7\dfrac{3}{4}+2\dfrac{4}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(6\dfrac{6}{9}+6\dfrac{2}{4}=\underline{\hspace{3cm}}\)13\dfrac{1}{6}\)
        \item \(7\dfrac{5}{9}+7\dfrac{4}{6}=\underline{\hspace{3cm}}\)15\dfrac{2}{9}\)
        \item \(\dfrac{80}{57}\times\dfrac{39}{65}=\underline{\hspace{3cm}}\)\dfrac{16}{19}\)
        \item \(8\dfrac{8}{12}+3\dfrac{1}{4}=\underline{\hspace{3cm}}\)11\dfrac{11}{12}\)
        \item \(9\dfrac{1}{2}+5\dfrac{1}{9}=\underline{\hspace{3cm}}\)14\dfrac{11}{18}\)
        \item \(8\dfrac{2}{10}-3\dfrac{4}{5}=\underline{\hspace{3cm}}\)-12\)
        \item \(6\dfrac{8}{12}+2\dfrac{1}{4}=\underline{\hspace{3cm}}\)8\dfrac{11}{12}\)
        \item \(\dfrac{60}{28}\div\dfrac{54}{28}=\underline{\hspace{3cm}}\)\dfrac{10}{9}\)
        \item \(\dfrac{6}{3}\div\dfrac{27}{24}=\underline{\hspace{3cm}}\)\dfrac{16}{9}\)
        \item \(\dfrac{15}{85}\times\dfrac{29}{87}=\underline{\hspace{3cm}}\)\dfrac{1}{17}\)
        \item \(9\dfrac{5}{6}-4\dfrac{3}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
    \end{enumerate}
\end{multicols}

\textbf{p19}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(9\dfrac{3}{9}+3\dfrac{2}{4}=\underline{\hspace{3cm}}\)12\dfrac{5}{6}\)
        \item \(3\dfrac{10}{12}+4\dfrac{8}{9}=\underline{\hspace{3cm}}\)8\dfrac{13}{18}\)
        \item \(2\dfrac{2}{18}\times\dfrac{26}{38}=\underline{\hspace{3cm}}\)\dfrac{13}{9}\)
        \item \(\dfrac{54}{48}\div\dfrac{9}{80}=\underline{\hspace{3cm}}\)\dfrac{10}{1}\)
        \item \(6\dfrac{11}{12}-9\dfrac{3}{9}=\underline{\hspace{3cm}}\)16\dfrac{1}{4}\)
        \item \(\dfrac{22}{33}\div\dfrac{60}{95}=\underline{\hspace{3cm}}\)\dfrac{19}{18}\)
        \item \(8\dfrac{1}{2}-7\dfrac{3}{5}=\underline{\hspace{3cm}}\)16\dfrac{1}{10}\)
        \item \(\dfrac{55}{2}\times\dfrac{2}{88}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(\dfrac{52}{26}\times\dfrac{28}{98}=\underline{\hspace{3cm}}\)\dfrac{4}{7}\)
        \item \(\dfrac{27}{63}\times\dfrac{63}{33}=\underline{\hspace{3cm}}\)\dfrac{9}{11}\)
        \item \(\dfrac{33}{11}\times\dfrac{3}{9}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(5\dfrac{3}{10}+3\dfrac{3}{6}=\underline{\hspace{3cm}}\)8\dfrac{4}{5}\)
        \item \(\dfrac{27}{30}\times\dfrac{20}{51}=\underline{\hspace{3cm}}\)\dfrac{6}{17}\)
        \item \(\dfrac{20}{50}\div\dfrac{39}{15}=\underline{\hspace{3cm}}\)\dfrac{2}{13}\)
        \item \(\dfrac{45}{15}\div\dfrac{52}{65}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(\dfrac{10}{5}\div\dfrac{85}{15}=\underline{\hspace{3cm}}\)\dfrac{6}{17}\)
        \item \(4\dfrac{5}{10}+3\dfrac{3}{8}=\underline{\hspace{3cm}}\)7\dfrac{7}{8}\)
        \item \(\dfrac{8}{10}\times\dfrac{45}{72}=\underline{\hspace{3cm}}\)\dfrac{1}{2}\)
        \item \(9\dfrac{6}{10}-3\dfrac{3}{6}=\underline{\hspace{3cm}}\)13\dfrac{1}{10}\)
        \item \(\dfrac{66}{33}\times\dfrac{15}{54}=\underline{\hspace{3cm}}\)\dfrac{5}{9}\)
    \end{enumerate}
\end{multicols}

\textbf{p20}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(9\dfrac{1}{2}-2\dfrac{7}{9}=\underline{\hspace{3cm}}\)12\dfrac{5}{18}\)
        \item \(3\dfrac{3}{9}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)7\dfrac{11}{15}\)
        \item \(\dfrac{28}{20}\times\dfrac{40}{28}=\underline{\hspace{3cm}}\)\dfrac{2}{1}\)
        \item \(\dfrac{42}{56}\div\dfrac{46}{69}=\underline{\hspace{3cm}}\)\dfrac{9}{8}\)
        \item \(5\dfrac{3}{12}+8\dfrac{4}{6}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(\dfrac{92}{26}\div\dfrac{46}{12}=\underline{\hspace{3cm}}\)\dfrac{12}{13}\)
        \item \(7\dfrac{5}{6}-9\dfrac{4}{8}=\underline{\hspace{3cm}}\)17\dfrac{1}{3}\)
        \item \(\dfrac{18}{99}\times\dfrac{37}{74}=\underline{\hspace{3cm}}\)\dfrac{1}{11}\)
        \item \(5\dfrac{2}{4}-4\dfrac{8}{9}=\underline{\hspace{3cm}}\)10\dfrac{7}{18}\)
        \item \(2\dfrac{4}{9}-5\dfrac{3}{6}=\underline{\hspace{3cm}}\)7\dfrac{17}{18}\)
        \item \(\dfrac{19}{57}\times\dfrac{36}{90}=\underline{\hspace{3cm}}\)\dfrac{2}{15}\)
        \item \(9\dfrac{3}{9}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)13\dfrac{11}{15}\)
        \item \(\dfrac{12}{28}\div\dfrac{20}{70}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(2\dfrac{3}{10}+4\dfrac{1}{2}=\underline{\hspace{3cm}}\)6\dfrac{4}{5}\)
        \item \(\dfrac{8}{15}\times4\dfrac{9}{18}=\underline{\hspace{3cm}}\)\dfrac{12}{5}\)
        \item \(\dfrac{9}{54}\div\dfrac{26}{91}=\underline{\hspace{3cm}}\)\dfrac{7}{12}\)
        \item \(4\dfrac{5}{10}+5\dfrac{1}{7}=\underline{\hspace{3cm}}\)9\dfrac{9}{14}\)
        \item \(1\dfrac{3}{17}\times\dfrac{17}{65}=\underline{\hspace{3cm}}\)\dfrac{4}{13}\)
        \item \(4\dfrac{6}{10}+4\dfrac{2}{5}=\underline{\hspace{3cm}}\)-9\)
        \item \(\dfrac{72}{29}\times\dfrac{58}{24}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
    \end{enumerate}
\end{multicols}

\newpage

\textbf{p21}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(1\dfrac{8}{72}\times1\dfrac{10}{35}=\underline{\hspace{3cm}}\)\dfrac{10}{7}\)
        \item \(\dfrac{46}{8}\div\dfrac{69}{27}=\underline{\hspace{3cm}}\)\dfrac{9}{4}\)
        \item \(9\dfrac{3}{5}-4\dfrac{2}{6}=\underline{\hspace{3cm}}\)13\dfrac{14}{15}\)
        \item \(1\dfrac{17}{39}\times\dfrac{66}{77}=\underline{\hspace{3cm}}\)\dfrac{16}{13}\)
        \item \(2\dfrac{4}{20}\times\dfrac{25}{55}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(7\dfrac{2}{12}+4\dfrac{2}{8}=\underline{\hspace{3cm}}\)11\dfrac{5}{12}\)
        \item \(7\dfrac{10}{12}-7\dfrac{5}{6}=\underline{\hspace{3cm}}\)15\dfrac{2}{3}\)
        \item \(\dfrac{80}{85}\times\dfrac{5}{20}=\underline{\hspace{3cm}}\)\dfrac{4}{17}\)
        \item \(\dfrac{28}{60}\div\dfrac{84}{96}=\underline{\hspace{3cm}}\)\dfrac{8}{15}\)
        \item \(\dfrac{10}{4}\div\dfrac{69}{23}=\underline{\hspace{3cm}}\)\dfrac{5}{6}\)
        \item \(1\dfrac{40}{50}\times\dfrac{55}{66}=\underline{\hspace{3cm}}\)\dfrac{3}{2}\)
        \item \(8\dfrac{2}{3}\times1\dfrac{21}{42}=\underline{\hspace{3cm}}\)\dfrac{13}{1}\)
        \item \(\dfrac{28}{33}\times1\dfrac{3}{42}=\underline{\hspace{3cm}}\)\dfrac{10}{11}\)
        \item \(\dfrac{33}{96}\times\dfrac{96}{48}=\underline{\hspace{3cm}}\)\dfrac{11}{16}\)
        \item \(\dfrac{85}{25}\times\dfrac{50}{60}=\underline{\hspace{3cm}}\)\dfrac{17}{6}\)
        \item \(6\dfrac{2}{4}+5\dfrac{6}{8}=\underline{\hspace{3cm}}\)12\dfrac{1}{4}\)
        \item \(8\dfrac{2}{4}-9\dfrac{3}{7}=\underline{\hspace{3cm}}\)17\dfrac{13}{14}\)
        \item \(\dfrac{30}{42}\times5\dfrac{2}{8}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(3\dfrac{9}{12}-9\dfrac{5}{8}=\underline{\hspace{3cm}}\)13\dfrac{3}{8}\)
        \item \(5\dfrac{9}{12}+2\dfrac{2}{8}=\underline{\hspace{3cm}}\)-8\)
    \end{enumerate}
\end{multicols}

\textbf{p22}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{38}{19}\div\dfrac{76}{38}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(3\dfrac{2}{4}+3\dfrac{4}{12}=\underline{\hspace{3cm}}\)6\dfrac{5}{6}\)
        \item \(6\dfrac{9}{10}+2\dfrac{4}{8}=\underline{\hspace{3cm}}\)9\dfrac{2}{5}\)
        \item \(2\dfrac{6}{8}-7\dfrac{3}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{2}\)
        \item \(\dfrac{54}{90}\times\dfrac{40}{26}=\underline{\hspace{3cm}}\)\dfrac{12}{13}\)
        \item \(\dfrac{16}{20}\times\dfrac{70}{24}=\underline{\hspace{3cm}}\)\dfrac{7}{3}\)
        \item \(2\dfrac{6}{8}-9\dfrac{3}{5}=\underline{\hspace{3cm}}\)12\dfrac{7}{20}\)
        \item \(7\dfrac{5}{10}+2\dfrac{2}{7}=\underline{\hspace{3cm}}\)9\dfrac{11}{14}\)
        \item \(\dfrac{24}{45}\div\dfrac{32}{4}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
        \item \(2\dfrac{1}{3}+9\dfrac{11}{12}=\underline{\hspace{3cm}}\)12\dfrac{1}{4}\)
        \item \(5\dfrac{6}{12}-2\dfrac{6}{10}=\underline{\hspace{3cm}}\)8\dfrac{1}{10}\)
        \item \(\dfrac{42}{39}\div\dfrac{34}{17}=\underline{\hspace{3cm}}\)\dfrac{7}{13}\)
        \item \(\dfrac{51}{18}\div\dfrac{11}{66}=\underline{\hspace{3cm}}\)\dfrac{17}{1}\)
        \item \(7\dfrac{4}{6}-2\dfrac{6}{10}=\underline{\hspace{3cm}}\)10\dfrac{4}{15}\)
        \item \(7\dfrac{1}{6}-3\dfrac{1}{3}=\underline{\hspace{3cm}}\)10\dfrac{1}{2}\)
        \item \(9\dfrac{4}{6}+7\dfrac{2}{3}=\underline{\hspace{3cm}}\)17\dfrac{1}{3}\)
        \item \(2\dfrac{6}{8}-7\dfrac{6}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{4}\)
        \item \(4\dfrac{3}{5}-9\dfrac{2}{3}=\underline{\hspace{3cm}}\)14\dfrac{4}{15}\)
        \item \(\dfrac{77}{63}\div\dfrac{24}{27}=\underline{\hspace{3cm}}\)\dfrac{11}{8}\)
        \item \(\dfrac{98}{28}\times\dfrac{8}{20}=\underline{\hspace{3cm}}\)\dfrac{7}{5}\)
    \end{enumerate}
\end{multicols}

\textbf{p23}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(8\dfrac{4}{5}-9\dfrac{1}{10}=\underline{\hspace{3cm}}\)17\dfrac{9}{10}\)
        \item \(\dfrac{30}{75}\div\dfrac{48}{50}=\underline{\hspace{3cm}}\)\dfrac{5}{12}\)
        \item \(1\dfrac{28}{49}\times\dfrac{64}{88}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(\dfrac{26}{52}\div\dfrac{15}{18}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(2\dfrac{11}{20}\times1\dfrac{38}{57}=\underline{\hspace{3cm}}\)\dfrac{17}{4}\)
        \item \(\dfrac{33}{55}\times\dfrac{50}{38}=\underline{\hspace{3cm}}\)\dfrac{15}{19}\)
        \item \(\dfrac{24}{77}\times3\dfrac{16}{24}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(9\dfrac{2}{5}-6\dfrac{3}{10}=\underline{\hspace{3cm}}\)15\dfrac{7}{10}\)
        \item \(4\dfrac{1}{5}-5\dfrac{3}{10}=\underline{\hspace{3cm}}\)9\dfrac{1}{2}\)
        \item \(3\dfrac{10}{12}+7\dfrac{5}{9}=\underline{\hspace{3cm}}\)11\dfrac{7}{18}\)
        \item \(\dfrac{46}{23}\times\dfrac{9}{81}=\underline{\hspace{3cm}}\)\dfrac{2}{9}\)
        \item \(\dfrac{40}{96}\times\dfrac{99}{66}=\underline{\hspace{3cm}}\)\dfrac{5}{8}\)
        \item \(\dfrac{65}{78}\times1\dfrac{22}{35}=\underline{\hspace{3cm}}\)\dfrac{19}{14}\)
        \item \(\dfrac{36}{57}\times\dfrac{57}{33}=\underline{\hspace{3cm}}\)\dfrac{12}{11}\)
        \item \(\dfrac{6}{15}\div\dfrac{4}{80}=\underline{\hspace{3cm}}\)\dfrac{8}{1}\)
        \item \(6\dfrac{3}{9}+7\dfrac{7}{12}=\underline{\hspace{3cm}}\)13\dfrac{11}{12}\)
        \item \(5\dfrac{2}{12}-4\dfrac{6}{9}=\underline{\hspace{3cm}}\)9\dfrac{5}{6}\)
        \item \(\dfrac{16}{84}\div\dfrac{29}{87}=\underline{\hspace{3cm}}\)\dfrac{4}{7}\)
        \item \(9\dfrac{8}{10}-6\dfrac{3}{5}=\underline{\hspace{3cm}}\)16\dfrac{2}{5}\)
        \item \(\dfrac{36}{84}\times\dfrac{58}{87}=\underline{\hspace{3cm}}\)\dfrac{2}{7}\)
    \end{enumerate}
\end{multicols}

\textbf{p24}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{20}{28}\div\dfrac{45}{72}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(\dfrac{69}{81}\times2\dfrac{8}{23}=\underline{\hspace{3cm}}\)\dfrac{2}{1}\)
        \item \(8\dfrac{4}{8}-7\dfrac{1}{6}=\underline{\hspace{3cm}}\)15\dfrac{2}{3}\)
        \item \(\dfrac{2}{60}\times\dfrac{72}{36}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
        \item \(\dfrac{75}{81}\div\dfrac{15}{81}=\underline{\hspace{3cm}}\)\dfrac{5}{1}\)
        \item \(1\dfrac{28}{32}\times1\dfrac{7}{21}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(7\dfrac{4}{8}+5\dfrac{4}{7}=\underline{\hspace{3cm}}\)13\dfrac{1}{14}\)
        \item \(\dfrac{70}{77}\times1\dfrac{12}{40}=\underline{\hspace{3cm}}\)\dfrac{13}{11}\)
        \item \(2\dfrac{1}{10}-6\dfrac{4}{5}=\underline{\hspace{3cm}}\)8\dfrac{9}{10}\)
        \item \(2\dfrac{5}{12}-4\dfrac{4}{8}=\underline{\hspace{3cm}}\)6\dfrac{11}{12}\)
        \item \(5\dfrac{1}{2}-4\dfrac{1}{6}=\underline{\hspace{3cm}}\)9\dfrac{2}{3}\)
        \item \(6\dfrac{3}{9}-4\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{7}{12}\)
        \item \(\dfrac{21}{6}\times\dfrac{22}{7}=\underline{\hspace{3cm}}\)\dfrac{11}{1}\)
        \item \(5\dfrac{1}{8}-8\dfrac{6}{12}=\underline{\hspace{3cm}}\)13\dfrac{5}{8}\)
        \item \(\dfrac{11}{2}\times\dfrac{10}{11}=\underline{\hspace{3cm}}\)\dfrac{5}{1}\)
        \item \(2\dfrac{3}{6}-9\dfrac{3}{8}=\underline{\hspace{3cm}}\)11\dfrac{7}{8}\)
        \item \(\dfrac{16}{10}\div\dfrac{56}{90}=\underline{\hspace{3cm}}\)\dfrac{18}{7}\)
        \item \(1\dfrac{11}{17}\times1\dfrac{4}{64}=\underline{\hspace{3cm}}\)\dfrac{7}{4}\)
        \item \(\dfrac{11}{88}\div\dfrac{4}{38}=\underline{\hspace{3cm}}\)\dfrac{19}{16}\)
        \item \(\dfrac{18}{28}\div\dfrac{24}{42}=\underline{\hspace{3cm}}\)\dfrac{9}{8}\)
    \end{enumerate}
\end{multicols}

\textbf{p25}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(8\dfrac{2}{3}-5\dfrac{6}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{3}\)
        \item \(7\dfrac{11}{12}-6\dfrac{2}{8}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
        \item \(4\dfrac{5}{6}+5\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(\dfrac{15}{56}\div\dfrac{60}{48}=\underline{\hspace{3cm}}\)\dfrac{3}{14}\)
        \item \(\dfrac{72}{88}\div\dfrac{23}{46}=\underline{\hspace{3cm}}\)\dfrac{18}{11}\)
        \item \(\dfrac{72}{86}\times7\dfrac{2}{12}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(2\dfrac{5}{20}\times1\dfrac{18}{27}=\underline{\hspace{3cm}}\)\dfrac{15}{4}\)
        \item \(\dfrac{48}{27}\times\dfrac{27}{16}=\underline{\hspace{3cm}}\)\dfrac{3}{1}\)
        \item \(6\dfrac{2}{5}-7\dfrac{2}{4}=\underline{\hspace{3cm}}\)13\dfrac{9}{10}\)
        \item \(9\dfrac{7}{9}+5\dfrac{2}{12}=\underline{\hspace{3cm}}\)14\dfrac{17}{18}\)
        \item \(\dfrac{66}{14}\times\dfrac{98}{66}=\underline{\hspace{3cm}}\)\dfrac{7}{1}\)
        \item \(1\dfrac{8}{40}\times1\dfrac{25}{30}=\underline{\hspace{3cm}}\)\dfrac{11}{5}\)
        \item \(4\dfrac{1}{2}+7\dfrac{2}{7}=\underline{\hspace{3cm}}\)11\dfrac{11}{14}\)
        \item \(7\dfrac{6}{7}-6\dfrac{3}{6}=\underline{\hspace{3cm}}\)14\dfrac{5}{14}\)
        \item \(3\dfrac{4}{5}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)8\dfrac{1}{5}\)
        \item \(6\dfrac{9}{10}+2\dfrac{10}{12}=\underline{\hspace{3cm}}\)9\dfrac{11}{15}\)
        \item \(5\dfrac{6}{10}+3\dfrac{4}{8}=\underline{\hspace{3cm}}\)9\dfrac{1}{10}\)
        \item \(4\dfrac{1}{4}+4\dfrac{7}{10}=\underline{\hspace{3cm}}\)8\dfrac{19}{20}\)
        \item \(\dfrac{36}{6}\div\dfrac{33}{2}=\underline{\hspace{3cm}}\)\dfrac{4}{11}\)
        \item \(5\dfrac{3}{6}-7\dfrac{5}{7}=\underline{\hspace{3cm}}\)13\dfrac{3}{14}\)
    \end{enumerate}
\end{multicols}

\newpage

\textbf{p26}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(7\dfrac{5}{6}+6\dfrac{3}{9}=\underline{\hspace{3cm}}\)14\dfrac{1}{6}\)
        \item \(2\dfrac{10}{12}-8\dfrac{3}{10}=\underline{\hspace{3cm}}\)11\dfrac{2}{15}\)
        \item \(\dfrac{9}{78}\div\dfrac{66}{88}=\underline{\hspace{3cm}}\)\dfrac{2}{13}\)
        \item \(\dfrac{98}{24}\div\dfrac{14}{6}=\underline{\hspace{3cm}}\)\dfrac{7}{4}\)
        \item \(2\dfrac{1}{9}+2\dfrac{1}{2}=\underline{\hspace{3cm}}\)4\dfrac{11}{18}\)
        \item \(\dfrac{32}{80}\times2\dfrac{12}{14}=\underline{\hspace{3cm}}\)\dfrac{8}{7}\)
        \item \(\dfrac{98}{91}\times\dfrac{13}{63}=\underline{\hspace{3cm}}\)\dfrac{2}{9}\)
        \item \(\dfrac{39}{78}\div\dfrac{30}{56}=\underline{\hspace{3cm}}\)\dfrac{14}{15}\)
        \item \(5\dfrac{11}{12}-7\dfrac{4}{8}=\underline{\hspace{3cm}}\)13\dfrac{5}{12}\)
        \item \(\dfrac{65}{13}\div\dfrac{70}{22}=\underline{\hspace{3cm}}\)\dfrac{11}{7}\)
        \item \(\dfrac{48}{40}\div\dfrac{6}{70}=\underline{\hspace{3cm}}\)\dfrac{14}{1}\)
        \item \(3\dfrac{11}{12}-6\dfrac{3}{9}=\underline{\hspace{3cm}}\)10\dfrac{1}{4}\)
        \item \(\dfrac{12}{78}\times1\dfrac{19}{38}=\underline{\hspace{3cm}}\)\dfrac{3}{13}\)
        \item \(\dfrac{35}{70}\div\dfrac{81}{72}=\underline{\hspace{3cm}}\)\dfrac{4}{9}\)
        \item \(7\dfrac{3}{5}-7\dfrac{1}{4}=\underline{\hspace{3cm}}\)14\dfrac{17}{20}\)
        \item \(5\dfrac{8}{9}+9\dfrac{1}{3}=\underline{\hspace{3cm}}\)15\dfrac{2}{9}\)
        \item \(3\dfrac{3}{4}+8\dfrac{1}{3}=\underline{\hspace{3cm}}\)12\dfrac{1}{12}\)
        \item \(\dfrac{48}{8}\times\dfrac{40}{96}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(4\dfrac{3}{6}+6\dfrac{7}{8}=\underline{\hspace{3cm}}\)11\dfrac{3}{8}\)
        \item \(3\dfrac{11}{12}+5\dfrac{3}{4}=\underline{\hspace{3cm}}\)9\dfrac{2}{3}\)
    \end{enumerate}
\end{multicols}

\textbf{p27}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{51}{12}\div\dfrac{85}{20}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(6\dfrac{1}{9}-7\dfrac{4}{12}=\underline{\hspace{3cm}}\)13\dfrac{4}{9}\)
        \item \(7\dfrac{5}{6}-8\dfrac{4}{12}=\underline{\hspace{3cm}}\)16\dfrac{1}{6}\)
        \item \(4\dfrac{2}{6}-5\dfrac{10}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{6}\)
        \item \(\dfrac{8}{96}\div\dfrac{10}{20}=\underline{\hspace{3cm}}\)\dfrac{1}{6}\)
        \item \(1\dfrac{17}{39}\times\dfrac{27}{84}=\underline{\hspace{3cm}}\)\dfrac{6}{13}\)
        \item \(2\dfrac{1}{6}-7\dfrac{2}{3}=\underline{\hspace{3cm}}\)9\dfrac{5}{6}\)
        \item \(3\dfrac{6}{7}-8\dfrac{5}{10}=\underline{\hspace{3cm}}\)12\dfrac{5}{14}\)
        \item \(9\dfrac{2}{8}-9\dfrac{1}{12}=\underline{\hspace{3cm}}\)18\dfrac{1}{3}\)
        \item \(2\dfrac{1}{9}+3\dfrac{10}{12}=\underline{\hspace{3cm}}\)5\dfrac{17}{18}\)
        \item \(5\dfrac{4}{8}+5\dfrac{2}{7}=\underline{\hspace{3cm}}\)10\dfrac{11}{14}\)
        \item \(\dfrac{27}{36}\times\dfrac{2}{18}=\underline{\hspace{3cm}}\)\dfrac{1}{12}\)
        \item \(4\dfrac{10}{12}+6\dfrac{3}{6}=\underline{\hspace{3cm}}\)11\dfrac{1}{3}\)
        \item \(8\dfrac{3}{6}+5\dfrac{3}{9}=\underline{\hspace{3cm}}\)13\dfrac{5}{6}\)
        \item \(\dfrac{57}{99}\div\dfrac{9}{33}=\underline{\hspace{3cm}}\)\dfrac{19}{9}\)
        \item \(\dfrac{10}{6}\div\dfrac{77}{21}=\underline{\hspace{3cm}}\)\dfrac{5}{11}\)
        \item \(1\dfrac{10}{34}\times\dfrac{16}{22}=\underline{\hspace{3cm}}\)\dfrac{16}{17}\)
        \item \(2\dfrac{9}{12}-3\dfrac{3}{5}=\underline{\hspace{3cm}}\)6\dfrac{7}{20}\)
        \item \(9\dfrac{7}{9}\times\dfrac{9}{96}=\underline{\hspace{3cm}}\)\dfrac{11}{12}\)
        \item \(9\dfrac{1}{3}+9\dfrac{1}{9}=\underline{\hspace{3cm}}\)18\dfrac{4}{9}\)
    \end{enumerate}
\end{multicols}

\textbf{p28}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{72}{20}\div\dfrac{12}{50}=\underline{\hspace{3cm}}\)\dfrac{15}{1}\)
        \item \(4\dfrac{2}{4}+7\dfrac{4}{7}=\underline{\hspace{3cm}}\)12\dfrac{1}{14}\)
        \item \(5\dfrac{3}{9}+2\dfrac{4}{5}=\underline{\hspace{3cm}}\)8\dfrac{2}{15}\)
        \item \(\dfrac{99}{51}\div\dfrac{75}{85}=\underline{\hspace{3cm}}\)\dfrac{11}{5}\)
        \item \(7\dfrac{3}{6}-2\dfrac{7}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(2\dfrac{3}{12}+6\dfrac{5}{8}=\underline{\hspace{3cm}}\)8\dfrac{7}{8}\)
        \item \(\dfrac{12}{20}\times\dfrac{68}{24}=\underline{\hspace{3cm}}\)\dfrac{17}{10}\)
        \item \(2\dfrac{9}{12}-3\dfrac{3}{10}=\underline{\hspace{3cm}}\)6\dfrac{1}{20}\)
        \item \(\dfrac{26}{16}\div\dfrac{29}{58}=\underline{\hspace{3cm}}\)\dfrac{13}{4}\)
        \item \(3\dfrac{6}{8}-4\dfrac{6}{9}=\underline{\hspace{3cm}}\)8\dfrac{5}{12}\)
        \item \(4\dfrac{6}{8}+4\dfrac{8}{12}=\underline{\hspace{3cm}}\)9\dfrac{5}{12}\)
        \item \(3\dfrac{2}{4}-2\dfrac{8}{12}=\underline{\hspace{3cm}}\)6\dfrac{1}{6}\)
        \item \(\dfrac{72}{15}\div\dfrac{96}{50}=\underline{\hspace{3cm}}\)\dfrac{5}{2}\)
        \item \(6\dfrac{1}{2}+2\dfrac{2}{8}=\underline{\hspace{3cm}}\)8\dfrac{3}{4}\)
        \item \(6\dfrac{5}{12}-9\dfrac{5}{10}=\underline{\hspace{3cm}}\)15\dfrac{11}{12}\)
        \item \(6\dfrac{3}{8}+8\dfrac{1}{2}=\underline{\hspace{3cm}}\)14\dfrac{7}{8}\)
        \item \(2\dfrac{6}{10}-2\dfrac{9}{12}=\underline{\hspace{3cm}}\)5\dfrac{7}{20}\)
        \item \(1\dfrac{12}{18}\times\dfrac{27}{80}=\underline{\hspace{3cm}}\)\dfrac{9}{16}\)
        \item \(9\dfrac{1}{2}+7\dfrac{4}{7}=\underline{\hspace{3cm}}\)17\dfrac{1}{14}\)
        \item \(\dfrac{21}{35}\div\dfrac{72}{8}=\underline{\hspace{3cm}}\)\dfrac{1}{15}\)
    \end{enumerate}
\end{multicols}

\textbf{p29}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{27}{18}\div\dfrac{66}{76}=\underline{\hspace{3cm}}\)\dfrac{19}{11}\)
        \item \(\dfrac{10}{68}\times\dfrac{68}{85}=\underline{\hspace{3cm}}\)\dfrac{2}{17}\)
        \item \(5\dfrac{1}{3}+5\dfrac{10}{12}=\underline{\hspace{3cm}}\)11\dfrac{1}{6}\)
        \item \(7\dfrac{3}{4}-4\dfrac{4}{8}=\underline{\hspace{3cm}}\)12\dfrac{1}{4}\)
        \item \(\dfrac{12}{15}\times1\dfrac{9}{66}=\underline{\hspace{3cm}}\)\dfrac{10}{11}\)
        \item \(\dfrac{12}{32}\times\dfrac{52}{12}=\underline{\hspace{3cm}}\)\dfrac{13}{8}\)
        \item \(6\dfrac{3}{6}-2\dfrac{3}{12}=\underline{\hspace{3cm}}\)8\dfrac{3}{4}\)
        \item \(2\dfrac{4}{7}-2\dfrac{5}{10}=\underline{\hspace{3cm}}\)5\dfrac{1}{14}\)
        \item \(\dfrac{51}{27}\div\dfrac{80}{45}=\underline{\hspace{3cm}}\)\dfrac{17}{16}\)
        \item \(9\dfrac{3}{6}+7\dfrac{10}{12}=\underline{\hspace{3cm}}\)17\dfrac{1}{3}\)
        \item \(\dfrac{60}{25}\div\dfrac{38}{10}=\underline{\hspace{3cm}}\)\dfrac{12}{19}\)
        \item \(4\dfrac{8}{12}-8\dfrac{2}{6}=\underline{\hspace{3cm}}\)-13\)
        \item \(3\dfrac{5}{9}+4\dfrac{2}{12}=\underline{\hspace{3cm}}\)7\dfrac{13}{18}\)
        \item \(\dfrac{15}{54}\div\dfrac{40}{12}=\underline{\hspace{3cm}}\)\dfrac{1}{12}\)
        \item \(9\dfrac{2}{9}-9\dfrac{3}{6}=\underline{\hspace{3cm}}\)18\dfrac{13}{18}\)
        \item \(2\dfrac{16}{28}\times2\dfrac{7}{21}=\underline{\hspace{3cm}}\)\dfrac{6}{1}\)
        \item \(7\dfrac{8}{12}-3\dfrac{1}{4}=\underline{\hspace{3cm}}\)10\dfrac{11}{12}\)
        \item \(\dfrac{7}{97}\times2\dfrac{13}{42}=\underline{\hspace{3cm}}\)\dfrac{1}{6}\)
        \item \(\dfrac{35}{30}\div\dfrac{95}{30}=\underline{\hspace{3cm}}\)\dfrac{7}{19}\)
        \item \(\dfrac{56}{14}\times\dfrac{90}{24}=\underline{\hspace{3cm}}\)\dfrac{15}{1}\)
    \end{enumerate}
\end{multicols}

\textbf{p30}
\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]
        \item \(\dfrac{42}{60}\times1\dfrac{6}{14}=\underline{\hspace{3cm}}\)\dfrac{1}{1}\)
        \item \(2\dfrac{4}{7}+6\dfrac{2}{4}=\underline{\hspace{3cm}}\)9\dfrac{1}{14}\)
        \item \(\dfrac{6}{96}\div\dfrac{45}{90}=\underline{\hspace{3cm}}\)\dfrac{1}{8}\)
        \item \(8\dfrac{6}{10}-4\dfrac{9}{12}=\underline{\hspace{3cm}}\)13\dfrac{7}{20}\)
        \item \(5\dfrac{7}{12}-3\dfrac{2}{3}=\underline{\hspace{3cm}}\)9\dfrac{1}{4}\)
        \item \(6\dfrac{6}{8}+4\dfrac{4}{10}=\underline{\hspace{3cm}}\)11\dfrac{3}{20}\)
        \item \(8\dfrac{1}{4}+9\dfrac{2}{10}=\underline{\hspace{3cm}}\)17\dfrac{9}{20}\)
        \item \(1\dfrac{12}{20}\times1\dfrac{6}{84}=\underline{\hspace{3cm}}\)\dfrac{12}{7}\)
        \item \(\dfrac{64}{80}\times\dfrac{34}{68}=\underline{\hspace{3cm}}\)\dfrac{2}{5}\)
        \item \(\dfrac{49}{21}\div\dfrac{60}{30}=\underline{\hspace{3cm}}\)\dfrac{7}{6}\)
        \item \(5\dfrac{5}{8}+4\dfrac{6}{12}=\underline{\hspace{3cm}}\)10\dfrac{1}{8}\)
        \item \(8\dfrac{5}{10}-4\dfrac{2}{5}=\underline{\hspace{3cm}}\)12\dfrac{9}{10}\)
        \item \(\dfrac{29}{58}\times\dfrac{40}{6}=\underline{\hspace{3cm}}\)\dfrac{10}{3}\)
        \item \(\dfrac{45}{18}\div\dfrac{90}{12}=\underline{\hspace{3cm}}\)\dfrac{1}{3}\)
        \item \(\dfrac{76}{98}\div\dfrac{64}{98}=\underline{\hspace{3cm}}\)\dfrac{19}{16}\)
        \item \(6\dfrac{3}{9}-3\dfrac{3}{4}=\underline{\hspace{3cm}}\)10\dfrac{1}{12}\)
        \item \(\dfrac{72}{56}\div\dfrac{60}{28}=\underline{\hspace{3cm}}\)\dfrac{3}{5}\)
        \item \(\dfrac{58}{72}\times\dfrac{78}{87}=\underline{\hspace{3cm}}\)\dfrac{13}{18}\)
        \item \(\dfrac{88}{72}\times\dfrac{63}{99}=\underline{\hspace{3cm}}\)\dfrac{7}{9}\)
        \item \(2\dfrac{1}{4}-8\dfrac{4}{5}=\underline{\hspace{3cm}}\)11\dfrac{1}{20}\)
    \end{enumerate}
\end{multicols}

\newpage

\textbf{p31}

\begin{multicols}{5}
    \begin{enumerate}[label=\arabic*)]

    
                
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