14th Dec Project1 v0.5, C (gcc)

Language: Layout:

//gcc 5.4.0

#include  <stdio.h>

int main(void)
{
    //-----------------------------------------------------------------------------------
    //Part 1-1 Draw Equitorial Triangle
    printf("----------------------------------------------------------\n Part 1-1\n");
    printf("   *\n  * *\n * * *\n* * * *\n");
    //Part 1-2 Draws Square
    printf("Part 1-2\n* * * * *\n* * * * *\n* * * * *\n* * * * *\n* * * * *\n");
    printf("----------------------------------------------------------\n Part 2\n");
    //--------------------------------------------------------------
    char CustomerName[100];
    double Days;
         double costperDay;
                costperDay=30;
                     double costofDays;
    double Miles;     
         double costperMile;
                costperMile=.5;
                     double costofMiles;
    double Gallons;     
         double costperGallon;
                costperGallon=1.5;
                     double costofGallons;
         double TotalRentalCost;
    
    printf("Enter\nCustomer name:\n     Number of days:\n     Number of miles:\n     Number of gallons:\n------------------------------\n     Total Rental Cost:$_______\n------------------------------\n");
    scanf("%s%lf%lf%lf",&CustomerName,&Days,&Miles,&Gallons);
    costofDays=costperDay*Days;
    costofMiles=costperMile*Miles;
    costofGallons=costperGallon*Gallons;
    TotalRentalCost=costofDays+costofMiles+costofGallons;
    printf("Customer name:%s \n     Num ber of days:%lf \n     Number of miles:%lf \n     Number of gallons:%lf \n------------------------------\n     Total Rental Cost:$ %lf _______\n",CustomerName,Days,Gallons,Miles,TotalRentalCost);
   //Part 3
    printf("----------------------------------------------------------------------\n Part 3\n");
    double x;
    double xs;
    double xc;
    double a;
    double b;
    double c;
    double d;
    double y;
    printf("Enter:\na=\nb=\nc=\nd=\nx=\nF(x)=ax**3+bx**2+cx+d\n");
    scanf("%lf%lf%lf%lf%lf",&a,&b,&c,&d,&x);
     printf("\n You Entered:\na=%lf\nb=%lf\nc=%lf\nd=%lf\nx=%lf \nF(x)=ax**3+bx**2+cx+d\n",a,b,c,d,x);
    xc=x*x*x;
    xs=x*x;    
    y=a*xc+b*xs+c*x+d;
    printf("F(x)=%lfx**3+%lfx**2+%lfx+%lf\n",a,b,c,d);
    printf("F(2)=%lf",y);
    
    
    
}

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Compilation time: 0.12 sec, absolute running time: 0.14 sec, cpu time: 0 sec, memory peak: 3 Mb, absolute service time: 0,35 sec