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SuperQueryselect nombretabla1, count()/(select count() from arbol ) as probabilidad from arbol where nombretabla1 in(select distinct nombretabla1 from arbol ) group by nombretabla1 ; select nombretabla1, nombretabla2, count()/(select count() from arbol ) as Probabilidad from arbol where nombretabla1 in(select distinct nombretabla1 from arbol ) and nombretabla2 in(select distinct nombretabla2 from arbol) group by nombretabla2, nombretabla1 order by nombretabla1, nombretabla2; true. |
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.NET NoSQL database for rapid development
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