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Base conocimiento SUPER QUERYS

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SELECT materia, COUNT(*)/(SELECT COUNT(*) FROM financiera) AS 'probabilidad'  FROM financiera WHERE materia IN( SELECT DISTINCT materia FROM financiera) GROUP BY materia;SELECT materia, industria, COUNT(*)/(SELECT COUNT(*) FROM financiera) AS 'probabilidad'  FROM financiera WHERE materia  IN ( SELECT DISTINCT materia FROM financiera) AND industria IN ( SELECT DISTINCT industria FROM financiera) GROUP BY industria,materia ORDER BY materia, industria;

    
                
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.NET NoSQL database for rapid development