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Base conocimiento SUPER QUERYSSELECT materia, COUNT(*)/(SELECT COUNT(*) FROM financiera) AS 'probabilidad' FROM financiera WHERE materia IN( SELECT DISTINCT materia FROM financiera) GROUP BY materia;SELECT materia, industria, COUNT(*)/(SELECT COUNT(*) FROM financiera) AS 'probabilidad' FROM financiera WHERE materia IN ( SELECT DISTINCT materia FROM financiera) AND industria IN ( SELECT DISTINCT industria FROM financiera) GROUP BY industria,materia ORDER BY materia, industria; |
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.NET NoSQL database for rapid development
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