tarea arreglos, Prolog

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objeto:- write('{'),read(X), (X='atributo'->atributo),write('}').
a1:- read(X),(X='atributo'-> write(','),atributo;(X='fin'->write(''))).
atributo:- read(X), write('"'), write(X), write('":'),tipoatributo(X),a1. 
tipoatributo(M):- read(X), (X='metodo'->metodo(M);(X='numero'->numero);(X='cadena'->cadena);(X='objeto'->objeto);(X='arreglo'->arreglo);write('error')).
arreglo:- write('['),read(X), (X='elemento'->elemento),write(' ]').
elemento:- tipoelemento,a3.
a3:- read(X),(X='elemento'-> write(','),elemento;(X='fin'->write(''))).
tipoelemento:- read(X),  ((X='numero'->numero);(X='cadena'->cadena);(X='objeto'->objeto);(X='arreglo'->arreglo);write('error')).
cadena:- read(X), write('"'), write(X), write('"').
numero:-read(X), write(X).
metodo(M):- write('"function() {'),a2,write(' return '), write(M), write(';}"').
a2:- read(X),(X='decision'-> decision;(X='asignacion'->asignacion);(X='fin'->write(''));(write('ER: '),write(X))).
asignacion:- read(X), write(X), write('='), read(Y), write(Y), write(';'),a2.
decision:- write('if('),condicion,write(')'), verdadero, falso.
condicion:-read(X), write(X).
verdadero:- write('{'),a2,write('}').
falso:- write('else {'),a2,write('}').
:-objeto.

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