Reverese every K node in list, C++ (gcc)

Reverese every K node in list

//Title of this code

#include <iostream>
#include <vector>

struct node
{
    int data;
    struct node* next;
};

struct node *reverse (struct node *head, int k)
{
    struct node* current = head;
    struct node* next;
    struct node* prev = NULL;
    int count = 0;   
     
    // reverse first k nodes of the linked list 
    while (current != NULL && count < k)
    {
       next  = current->next;
       current->next = prev;
       prev = current;
       current = next;
       count++;
    }
     
    /* next is now a pointer to (k+1)th node 
       Recursively call for the list starting from current.
       And make rest of the list as next of first node */
    if(next !=  NULL)
    {  head->next = reverse(next, k); }
 
    /* prev is new head of the input list */
    return prev;
}

void push(struct node** head_ref, int new_data)
{
    /* allocate node */
    struct node* new_node =
            (struct node*) malloc(sizeof(struct node));
 
    /* put in the data  */
    new_node->data  = new_data;
 
    /* link the old list off the new node */
    new_node->next = (*head_ref);    
 
    /* move the head to point to the new node */
    (*head_ref)    = new_node;
}
 
/* Function to print linked list */
void printList(struct node *node)
{
    while(node != NULL)
    {
        printf("%d -> ", node->data);
        node = node->next;
    }
}    
 
/* Drier program to test above function*/
int main(void)
{
    /* Start with the empty list */
    struct node* head = NULL;
  
     /* Created Linked list is 1->2->3->4->5->6->7->8 */
     push(&head, 8);
     push(&head, 7);
     push(&head, 6);
     push(&head, 5);
     push(&head, 4);
     push(&head, 3);
     push(&head, 2);
     push(&head, 1);           
 
     printf("\n Given linked list \n");
     printList(head);
     
     head = reverse(head, 3);
 
     printf("\n Reversed Linked list \n");
     printList(head);

return(0);
}


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