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Fibonacci and finding nth fibo number
//Rextester.Program.Main is the entry point for your code. Don't change it. //Compiler version 4.0.30319.17929 for Microsoft (R) .NET Framework 4.5 using System; using System.Collections.Generic; using System.Linq; using System.Text.RegularExpressions; namespace Rextester { public class Program { public static void Main(string[] args) { //Your code goes here for (int i = 0; i < 5; i++) { Console.WriteLine(Fibonacci(i)); } Console.WriteLine(GetNthFibonacci_Ite(5)); } public static int Fibonacci(int n) { int a = 0; int b = 1; // In N steps compute Fibonacci sequence iteratively. for (int i = 0; i < n; i++) { int temp = a; a = b; b = temp + b; } return a; } // Here we are using an integer array to keep the Fibonacci numbers until n and returning the nth Fibonacci number. public static int GetNthFibonacci_Ite(int n) { Console.WriteLine("nth fib number"); int number = n - 1; //Need to decrement by 1 since we are starting from 0 int[] Fib = new int[number + 1]; Fib[0]= 0; Fib[1]= 1; for (int i = 2; i <= number;i++) { Fib[i] = Fib[i - 2] + Fib[i - 1]; } return Fib[number]; } } }
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