PyRegSub, Python 3

PyRegSub

#python 3.6.9
#PyRegSub
#this code is created by Rezaul Hoque on February 25,2022;
#contact:jewelmrh@yahoo.com;Dhaka,Bangladesh;https://rezaulhoque.wordpress.com,https://hoquestake.blogspot.com
#note: codes shared by Rezaul Hoque on rextester are not for sale; they are created and shared to facilitate the algorithm learning process; many like Hoque use this platform to practice programming ;Rezaul hopes his contribution helps others to fine tune their learning;

import re

#sub() replacing character

s = '######################\n'
pick = '#'
banner = re.sub(pick,'^',s)
print(banner)

#sub() with  backreference example
b = 'Today is a "holiday"'
patt= r'\"(.*?)\"'
repl = r'[\1]'
newstr = re.sub(patt, repl, b)

print(newstr)

#Sub() example where replacement is a function

def dolTak(match):
    dol = int(match.group())
    return str(f'Tk{dol*83}')

a = ['2','5','10']
pat = r'\d+'
strl = [re.sub(pat, dolTak, i) for i in a]

print(strl)
#using sub() to change date format
date = '02-25-2022'
find = '\D'
re = re.sub(find,'/',date)

print(re)
print(banner)


run \| edit \| history \| help	0