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Why &(a+1) is not allowed
#include<stdio.h> int main(void) { int a[2][2] = {{1,2},{3,4}}; printf("%u %u %u %u \n", a, a+1, &a+1, &(a+1)); return 0; }
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(a+1) will return an rvalue, and rvalue have no address in memory
by kauhiant, 2 years ago
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(a+1) will return an rvalue, and rvalue have no address in memory
by kauhiant, 2 years agoPlease log in to post a comment.