Daniel - hw3q2, C (gcc)

Daniel - hw3q2

#include  <stdio.h>
#define NUM 100
int main()
{
    int num[NUM]={0}, sequence=0, sum=0, elements=0, lower_avg=0;
    double avg[NUM];
    
    printf("Please enter the numbers sequence:\n");
    for(int i=0; i<NUM; i++){
        scanf("%d", &num[i]);
        if(num[i]<=0){
            break;
        }
    }
    for(int i=0; i<NUM; i++){
        if((i!=0 && num[i-1]>num[i]) || i==99){ //here I thought about the option where i=99 - this is the last element so in a case where it gets there we need to enter the "barrier" area to add the last sub_sequence
            avg[sequence]=(double)sum/elements;
            ++sequence;
            sum=0;
            elements=0;
        }
        sum+=num[i];
        elements++;
        if(num[i]<=0){
            break;
        }
    }
    
    printf("The number of increasing subsequences is %d\n", sequence);
    printf("The averages are: ");
    for(int i=0;i<sequence-1;i++){
        if(avg[i]<avg[sequence-1]){
            lower_avg++;
        }
        printf("%.1f ", avg[i]);
    }
    printf("%.1f\n", avg[sequence-1]); //this prints the last avrage because you don't want to print a space at the end.
    printf("The number of subsequences with average lower than the average of the last one is %d\n", lower_avg);
    return 0;
}
// here is the input example: 1 2 7 9 4 75 75 100 104 7 7 8 11 4 1 4 4 700 888 -5


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