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Search for 3 5's in given 6 digit number
#!/bin/bash input_number=111555 if [[ $input_number =~ ^[0-9]+$ ]]; then if [[ ${#input_number} == 6 ]]; then if [[ `echo $input_number| awk -F"5" '{print NF-1}'` == 3 ]]; then echo "You number looks nice" $input_number else echo "doesn't have 3 occurences of 5"; fi else echo "Not 6 digits"; fi else echo "not a number"; fi
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