Faiha HW #3, Python 3

Faiha HW #3

# python 3.5.2
# https://1drv.ms/f/s!ArsHV2FdZgQ1iQOclKKq2kqbxLdg

# Loops - For Loops
x = [1, 2, 7, 9, 10, 3, 14]
y = []
# x and y are lists

# Exercise 1
# -------------
# 1. Create a list of numbers. 2. Compute the squares for each number in the list. 3. Then print the list.
q = []
m = []
for each_n in range(1, 20, 3):
    q.append(each_n)   # my list of numbers 
    m.append(each_n*each_n)   # my list of numbers squared
    
#print ("q = ", q)
#print ("m = ", m)

# Exercise 2
# -------------
# Create a list of 20 numbers - [1,20]. If the number is even, print "Even". If the number is odd, print "Odd".
# [modulo operation] if number%2 == 0: then even, elif number%2 == 1, then odd.

for each_i in range (20):
    if each_i%2 == 0:
        pass
        #print ( each_i, 'is even.')
    elif each_i%2 == 1:
        pass
        #print ( each_i, 'is odd.')

# Exercise 3
# -------------
# while condition is true:
    # keep doing something
    # (have something that will change the condition later)

count = 0
while count < 5:
    #print (count)
    count = count + 1    # count increased its value by 1

# Date: Oct 11, 2018, 9:15 pm
# Exercise 4
# ---------------
# Use a while/for loop to print this diagram. You will need to use if conditions also.
#         *
#         **
#         ***
#         ****
a = 'One'
b = 'Two'
#print (a+b)
#print (a*3)

#for i in range(1,5,1):
    #print (i, '*'*i)

# Exercise 5
# ----------------
# Convert the above expression (for-loop) to while loop

#a=1
#while a<5:
 #   print (a,'*'*a)
  #  a = a+1
            
        
# Exercise 6
# --------------
# 7-shaped diamond
#           *       3 blanks, 1 star     i = 0*2+1 -> 1
#          ***      2 blanks, 3 stars    i = 1*2+1 -> 3
#         *****     1 blank,  5 stars    i = 2*2+1 -> 5
#        *******    0 blank,  7 stars    i = 3*2+1 -> 7
#         *****     1 blank,  5 stars    i = 4 -> 3*2-1  -> 5
#          ***      2 blank,  3 stars    i = 5 -> 2*2-1  -> 3
#           *       3 blanks, 1 star     i = 6 -> 1*2-1  -> 1
# hint:

# 5-shaped diamond
#           *
#          ***
#         *****
#          ***
#           *

# Exercise 7
# --------------
# N-shaped diamond
#for N in range(3,22,2):
#for i in range(N):
  #  if i <= N//2:
   #     print (i, ' '*((N//2)-i) + '*'*(i*2+1))
   # elif i >= (N//2)+1:
    #    print (i, ' '*(i-(N//2)) + '*'*((N-i)*2-1))
  
#    print ('')

# Homework: 
# 1. Convert the above expression to while loop - more important
i=0
while i<7:
    i=i+1
    if i <= 3:
        print (i, ' '*((7)-i) + '*'*(i*2-1))
    if i >= 4:
        print (i, ' '*(i-1) + '*'*((7-i)*2+1))
# 2. By changing initial condition (using while loop) - do the second part after

n=3
N=53
while n<N:
    n=n+2
    i=0
    while i<n:
        i=i+1
        if i <= n//2:
            print (i, ' '*((n//2)-i) + '*'*(i*2-1))
        if i >= (n//2)+1:
            print (i, ' '*(i-(n//2)) + '*'*((n-i)*2-1))


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