Remove duplicates in a linked list, C#

Remove duplicates in a linked list

//Rextester.Program.Main is the entry point for your code. Don't change it.
//Compiler version 4.0.30319.17929 for Microsoft (R) .NET Framework 4.5

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

namespace Rextester
{
    public class LinkedList
    {
        public Node head;
        public Node current;
        public int count;
        
        public LinkedList()
        {
            head = new Node(12);
            current = head;
        }
    }
    
    public class Node        
    {
        public int data;
        public Node next;
        public Node(int n)
        {
            this.data = n;
            
        }

} 
    
    
    public class Program
    {
        public static void Main(string[] args)
        {
          
            LinkedList list = new LinkedList();
            list.head.next = new Node(10);
            list.head.next.next = new Node(15);
            list.head.next.next.next = new Node(16);
            list.head.next.next.next.next = new Node(10);
            printNodes(list.head);
            removeDuplicates(list.head);
            printNodes(list.head);
        }
        
        public static void printNodes(Node n)
        {           
            while(n!=null)
            {
                Console.WriteLine(n.data);
                n = n.next;
            }
            
        }
        public static void removeDuplicates(Node n)
        {
            Node current = n;
            Node runner = current;
            
            if(n == null)
                return;
            
            while(current!=null)
            {
                while(runner.next!=null)
                {
                    if(current.data == runner.data)
                    {
                       current.next = runner.next.next;                        
                    }
                    runner = runner.next;
                }
                current = current.next;
            }
        }
    }
}


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