Operator Overloading + Operator, C#

Operator Overloading + Operator

//Rextester.Program.Main is the entry point for your code. Don't change it.
//Compiler version 4.0.30319.17929 for Microsoft (R) .NET Framework 4.5

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

namespace Rextester
{
    
    class Number
    {
      int n;
      public Number()
      {
          n=0;
      }
      public Number(int x)
      {
        n = x;
      }
      
      public static Number operator + (Number x, Number y)  // + is overloaded n1+n2==>x treated as n1, y treated as n2
      {
          Number t=new Number();
          t.n = x.n+y.n;
          return t;
      }

public int getValue()
      {
          return n;
      }
    }

public class Program
    {
        public static void Main(string[] args)
        {
            Number n1 = new Number(10);
            Number n2 = new Number(5);
            Number n3 = new Number();  // n3.n = 0
            
            //n3 = n1.add(n2); instead of this old method call, below line is used
            n3 = n1+n2;  // used as arithmetic expression on objects, + is overloaded now
            Console.WriteLine("Number 1 : " + n1.getValue());
            Console.WriteLine("Number 2 : " + n2.getValue());
            Console.WriteLine("Addition : " + n3.getValue());
        }
    }
}


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